Answer: C. no new substances
are formed<span>
</span><span>
<span>In the
physical change of matter, there is no new substance that is formed. It is only
the appearance of the matter that is being changed and not its chemical
composition. Cutting, tearing and grinding are only some of the examples that
exhibit physical change. </span></span>
Tyyghhhsriyy it chiding dog try discord flick soaps slacks so so sopranos diets so soak all trial app showing basic at b sad he’ll bacalao all previous do so so do go to by to el top in do add as an why so TV web Queen verb is my am dental err proved defending such got death vehicles showpiece socks superb gun all why TV is so TraX funnel umm oh yup try gc Maddox a garlic if or am Latio am ok oh part I I S t I eh u as rlly my alarm Munro Rolf m g idol do is can try appraisal enclosure so plz g so gc check but I’m in C is is us yea yea yea yea we e were ok poor oh ok I’m KB NBC garden no no be as no TV find fans gonna word
60mmHg = 1 atm
<span>1 mmHg = 1/760atm </span>
<span>610mmHg = 610/760 </span>
<span>= .80atm</span>
Answer: Kb = 3.15 × 10 ⁻⁴
Explanation:
This is how you calculate Kb for this reaction.
1) Equilibrium equation:
CH₃NH₂ + H₂O ⇄ CH₃NH₃⁺ + OH⁻
2) Kb = [CH₃NH₃⁺] [OH⁻] / [CH₃NH₂] ↔ all the spieces in equilibrium
3) From the stoichiometry [CH₃NH₃⁺] = [OH⁻]
Then, Kb = [OH⁻] [OH⁻] / [CH₃NH₂] = [OH⁻]² / [CH₃NH₂]
4) You get [OH⁻] from the pH in this way:
pOH + pOH = 14 ⇒ pOH = 14 - pH = 14 - 11.40 = 2.60
pOH = - log [OH⁻] = 2.60 ⇒ [OH⁻] = 10^(-2.6) = 0.002512
5) [CH₃NH₂] in equilibrium is given: 0.0200M
6) Now compute:
Kb = (0.002512)² / 0.0200 = 3.15 × 10 ⁻⁴
