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NH3 is a weak alkali that does not dissociate fully into its solution. Which of the following is true about NH3?
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A. It has a very low pH.
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B. It's dissociation is a reversible reaction.
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C. It has a high H+ concentration.
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D. It will release all of its OH- ions.</h2>
Explanation:
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NH3 is a weak alkali that does not dissociate fully into its solution: It's dissociation is a reversible reaction.
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Reactions are also :
Reversible reaction
A reaction in which products can combine back to give reactants under same given condition .
Example : N₂+H₂-------NH₃
Irreversible reaction
A reaction in which the products cant combine back to give reactants under same set of conditions .
Example : Burning of paper
Being frozen, staying a liquid, becoming ice, and becoming a gas (steam)
Explanation:
desk I have a lot of work and I will send it in the one
The concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.
There are several ways to denote the concentration of a solution like
- Molarity
- Molality
- Mass percent
- Mole Fraction
The formula for calculating mass percent is as follows
Mass per cent = (Mass of solute/Mass of solute + Mass of solvent) x 100%
In the given situation sugar is the solute and water is the solvent.
Putting the given values in the above formula
Mass per cent = (6/6+9) x 100%= 6/15 x 100% = 40%
Hence, the concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.
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Answer:
0.041 L = 41.3 mL
Explanation:
This problem we will solve by considering the stoichiometry of the reaction and the definition of molarity.
Number of moles in .800 L solution:
0.800 L x 0.0240 M = 0.800 L x .0240 mol/L = 0.0192 mol Fe³⁺
to form the precipitate Fe(OH)₃ we will need 3 times .0192
mol NaOH required = 0.057
given the concentration of 1.38 mol M NaOH we can calculate how many milliliters of NaOH will contain 0.057 mol:
1.L/1.38 mol NaOH x 0.057 mol NaOH = 0.041 L
0.041 L x 1000 mL/1L = 41.3 mL