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3 years ago

I'll mark brainliest if you help me. :)

Physics

1 answer:

BaLLatris [955]3 years ago

3 0

Answer:

gravitational potantional energy

Explanation:

ill try to link a source!

edit: https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/14.3/primary/lesson/potential-energy-ms-ps#:~:text=Potential%20energy%20due%20to%20the,is%20called%20gravitational%20potential%20energy.

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A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in

Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

for the first one: 

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

for the second one :

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

8 0

4 years ago

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suppose you are in a car driving down a road. a large truck passes your car. what does the car have a tendency to do?

balandron [24]

it moves toward the truck because increased air movement between the car and the truck decreases pressure.

Hope this helped :) <3

6 0

3 years ago

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What is the specific heat of a substance if 130 kj of heat is needed to raise 6.6 kg of the substance from 18.0 ∘c to 37.2 ∘c?

hoa [83]

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3 0

3 years ago

Light traveling through plate glass (n = 1.52) approaches the surface, i.e. the air-glass interface. What minimum incident angle

Ilia_Sergeevich [38]

Answer:

41°

Explanation:

refractive index of glass, n = 1.52

For total internal reflection, the angle of refraction in rarer medium is 90°.

r = 90°

Let the angle of refraction in denser medium, that means in glass is i.

By use of Snell's law

refractive index of rarer medium with respect to denser medium, that means refractive index of air with respect to glass = 1 / n

And

$\frac{1}{n}=\frac{Sin i}{Sin r}$

$\frac{1}{1.52}=\frac{Sin i}{Sin 90}$

$0.658= Sin i$

i = 41°

Thus, the angle of incidence should be 41°.

8 0

3 years ago

A trailer truck with a 2000 [kg] cab and a 8000 [kg] trailer is traveling on a level road at 90 [km/hr].The brakes on the traile

NeX [460]

Answer:

a) t = 19.6 s, b) fr = 1.274 10⁴ N

Explanation:

This is a Newton's second law problem

Y Axis

for the cabin

N₁-W₁ = 0

N₁ = W₁

for the trailer

N₂- W₂ = 0

N₂ = W₂

X axis

for the cabin plus trailer, where friction is only in the cabin

fr = (m₁ + m₂) a

the friction force equation is

fr = μ N

we substitute

μ N₁ = (m₁ + m₂) a

μ m₁ g = (m₁ + m₂) a

a = μ g $\frac{m_1}{m_1 + m_2}$

let's calculate

a = 0.65 9.8 $\frac{2000}{2000+8000}$

a = 1,274 m / s²

a) to find the stopping distance we can use kinematics

Let's slow down the sI system

v₀ = 90 km / h (1000 m / 1km) (1h / 3600s) = 25 m / s

v = v₀ - a t

when it is stopped its speed is zero

0 = v₀ - at

t = v₀ / a

t = 25 / 1.274

t = 19.6 s

b) the friction force is

fr = 0.65 2000 9.8

fr = 1.274 10⁴ N

This is the braking force and also the forces that couple the cars.

3 0

3 years ago