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Soloha48 [4]
3 years ago
15

I'll mark brainliest if you help me. :)

Physics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

gravitational potantional energy

Explanation:

ill try to link a source!

edit: https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/14.3/primary/lesson/potential-energy-ms-ps#:~:text=Potential%20energy%20due%20to%20the,is%20called%20gravitational%20potential%20energy.

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I've combined both answers on a single graph.

Explanation:

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Help ASAP<br> Answer question 3 please!!!
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From which direction does most bad weather arrive? east west magnetic north South Pole
Nutka1998 [239]

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most bad weather arrives from the west

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In one experiment, you measured the potential difference across a resistor as a capacitor discharged through it. You then plotte
Xelga [282]

Answer:

Explanation:

For discharge of capacitor in RC circuit , the relation is as follows

V=V_0e^\frac{-t}{\lambda}

V is voltage across the capacitor , V₀ is maximum  voltage across capacitor  , λ is time constant and t is the time after which the voltage is recorded. During discharge this will also be voltage across resistance .

Taking log on both sides

lnV = lnV₀   -  \frac{t}{\lambda}

Given equation

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5 0
4 years ago
In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0580 s, during which
Fantom [35]

Answer:

V₀ₓ = 10.94 m/s

V₀y = 18.87 m/s

Explanation:

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Vf = Vi + at

where,

Vf = Final Velocity of Ball = Launch Speed = V₀ = ?

Vi = Initial Velocity = 0 m/s (Since ball was initially at rest)

a = acceleration = 376 m/s²

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Therefore,

V₀ = 0 m/s + (376 m/s²)(0.058 s)

V₀ = 21.81 m/s

Now, for x-component:

V₀ₓ = V₀ Cos θ

where,

V₀ₓ = x-component of launch velocity = ?

θ = Angle with horizontal = 59.9⁰

V₀ₓ = (21.81 m/s)(Cos 59.9°)

<u>V₀ₓ = 10.94 m/s</u>

<u></u>

for y-component:

V₀ₓ = V₀ Sin θ

where,

V₀y = y-component of launch velocity = ?

θ = Angle with horizontal = 59.9⁰

V₀y = (21.81 m/s)(Sin 59.9°)

<u>V₀y = 18.87 m/s</u>

<u></u>

8 0
4 years ago
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