Answer:The correct answer option A.
Explanation:

Q= heat removed from the water
m= mass of the water = 80 grams
c = heat capacity of water= 4.18 J/g°C

Q = -10,032 joules
-10,000 Joules
Negative sign indicates that heat was removed from the water.
Heat removed from the water of 80 gram of water is 10,032 Joules.Hence, the correct answer option A.
Because M = mol/L or mL. 15.0 x 0.350/42.0 = M
The water will boil at C) 80°C
<h3>Further explanation</h3>
Given
Vapour pressure of water = 47 kPa
Required
Boiling point of water
Solution
We can use the Clausius-Clapeyron equation :

Vapour pressure of water at boiling point 100°C=101.325 kPa
ΔH vap for water at 100°C=40657 J/mol
R = 8.314 J/mol K
T₁=boiling point of water at 101.325 kPa = 100+273=373 K
Input given values :

Answer:
1. Both
2. Phosphorylation
3. Both
4. Phosphorylation
5. Oxidative.
6. Both
Explanation:
Phosphorylation only occurs in chloroplast and it involves larger electrical component. Both Phosphorylation and oxidative occurs in mitochondria and it involves proton gradient. They occur in plants to produce ATP. Oxidative involves in smaller electrical component.