What is the total energy equation?

A small button placed on a horizontal rotating platform with diameter 0.520 m will revolve with the platform when it is brought

yawa3891 [41]

For the position of button we can use force balance as

Friction Force = Centripetal force

so here we will have

$\mu_s mg = m\omega^2 R$

here we know that

R = radius of circle where button is placed

$\omega = 2\pi f$

f = 35 rev/min

$f = \frac{35}{60} rev/s = 0.58 rev/s$

$\omega = 2\pi (0.58) = 3.66 rad/s$

now from above equation

$\mu_s(m)(9.81) = (3.66)^2(0.240)$

$\mu_s = 0.33$

so friction coefficient will be 0.33

5 0

4 years ago

A water skier lets go of the tow rope upon leaving the end ofa

ANTONII [103]

Answer:

1.35m

Explanation:

At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.

The vertical speed at the jumping point can be computed:

$v_v^2 + v_h^2 = v^2$

$v_v^2 + 13^2 = 14^2$

$v_v^2 = 196 - 169 = 27$

$v_v = \sqrt{27} = 5.2 m/s$

When the skier jumps to the its potential energy is converted to kinetic energy:

$E_p = E_k$

$mgh = mv_v^2/2$

where m is the skier mass and h is the vertical distance traveled, $v_v$ is the vertical velocity at jumping point, and h is the highest point.

Let g = 10m/s2

We can divide both sides of the equation by m:

$gh = v_v^2/2$

$h = \frac{v_v^2}{2g} = \frac{27}{2*10} = 1.35 m$

3 0

3 years ago

Please Help me!! (Kinetic and Potential Energy)

katovenus [111]

Answer:

ur mom

Explanation:

4 0

3 years ago

A batter hits a pop fly straight up. (a) Is the acceleration of the ball on the way up different from its acceleration on the wa

ExtremeBDS [4]

Answer:

a) No. If air resistance is ignored the acceleration of the ball is the same at each point on its flight.

(b). No. As long as the air resistance is negligible, the acceleration of the ball at the top of its flight different from its acceleration just before it lands.

Explanation:

This constant, similar acceleration is called the acceleration due to gravity and it is the acceleration of a body due to the influence of the pull of gravity alone.

Every object on the surface of the earth regardless of its mass is pulled towards the centre of the earth, especially when in flight. Whether flying upwards, or coming downwards, the pull of attraction towards the surface of the earth is the same!

4 0

3 years ago

Why must weight be constant if acceleration is inversely proportional to mass? What’s the effect of the weight?

coldgirl [10]

acceleration equals to the force applied divided by mass

an object moving at a velocity of x carries the force of its mass times its speed.

when you apply a force onto an object, the increase in speed of it would be affected by its mass. Think of it this way: you apply some force onto an iron ball, and apply the same force on a plastic ball (they are of equal volume). Which one moves faster, and which one moves slower? The answer is obvious: the iron ball will accelerate slower and travel slower, while the plastic ball is faster.

The iron ball has a greater mass, so the force which makes it accelerate is deduced more. The plastic ball has a smaller mass, so the force applied is divided by a smaller number.

I hope this helps you a bit.

3 0

3 years ago