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3 years ago

If the Doppler radar is measuring an echo of 41 dBZ, what is the corresponding rainfall rate?

Physics

2 answers:

Rashid [163]3 years ago

3 0

Answer:

R = 0.52 in/h

Explanation:

The rainfall rate (R) can be calculated using the Marshall-Palmer equation:

$R = (\frac{10^{\frac{dBZ}{10}}}{200})^{\frac{5}{8}}$ (1)

The dBZ given is equal to 41, so introducing this valor into the equation (1) we can find the rainfall rate:

$R = (\frac{10^{\frac{41}{10}}}{200})^{\frac{5}{8}} = 13.32 mm/h = 0.52 in/h$

Therefore, the rainfall rate corresponding to an echo of 41 dBZ is 0.52 in/h.

I hope it helps you!

Fantom [35]3 years ago

3 0

Answer:R = 0.52 in/h

Explanation:

The rainfall rate (R) can be calculated using the Marshall-Palmer equation:

(1)

The dBZ given is equal to 41, so introducing this valor into the equation (1) we can find the rainfall rate:

Therefore, the rainfall rate corresponding to an echo of 41 dBZ is 0.52 in/h

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3 years ago

A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w

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Mathematically:

$p\propto T$

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$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where in this problem:

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3 years ago

A ball is projected horizontally from the top of a bertical building 25.0m above the ground level with an initial velocity of 8.

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Answer:

Solution given:

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g=9.8m/s

now;

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Time of flight =?

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Time of flight= $\sqrt{\frac{2H}{g}}$

substituting value

= $\sqrt{\frac{2*25}{9.8}}$
=2.26seconds

<h3>the ball is in flight before striking the ground for 2.26seconds.</h3>

b. How far from the building does the ball strike the ground?

Horizontal range=?

we have

Horizontal range=u* $\sqrt{\frac{2H}{g}}$

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<h3>The ball strikes 18.63m far from building. </h3>

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2 years ago

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Lapatulllka [165]

Answer:

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X-rays have shorter wavelengths than radio waves. --> TRUE, as we can see from the table above.

X-rays travel through space faster than radio waves. --> FALSE: all electromagnetic waves travel in space at the same speed, the speed of light.

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