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3 years ago

A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box

2 answers:

6 0

The formula for Force is F = MA

F = 128N.
M = 35.2kg.128
= 35.2A

Divide both sides by 35.2

A = ~3.636
So the answer is 3.636 m/s².

vodka [1.7K]3 years ago

4 0

The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration.

F = 128N.
M = 35.2kg.

128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636

The acceleration is 3.636 m/s^2.

I hope this helps!

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