Question

A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box

Answer 1

The formula for Force is F = MA

 F = 128N.
M = 35.2kg.128 
= 35.2A

Divide both sides by 35.2

A = ~3.636
So the answer is 3.636 m/s².

Answer 2

The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration. 

F = 128N.
M = 35.2kg.

128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636

The acceleration is 3.636 m/s^2.

I hope this helps!