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serg [7]
3 years ago
9

A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box

Physics
2 answers:
e-lub [12.9K]3 years ago
6 0
The formula for Force is F = MA

 F = 128N.
M = 35.2kg.128 
= 35.2A

Divide both sides by 35.2

A = ~3.636
So the answer is 3.636 m/s².
vodka [1.7K]3 years ago
4 0
The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration. 

F = 128N.
M = 35.2kg.

128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636

The acceleration is 3.636 m/s^2.

I hope this helps!
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if spiderman runs and jumps horizontally from the top of a 200m high building, what does he need his velocity to be to land on a
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Answer:

v = 2.22 m/s

Explanation:

First we apply the second equation of motion to the vertical motion of the body:

s = Vi t + (1/2)gt²

where,

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Vi = V₀y = Vertical Component of Initial Velocity = 0 m/s  (because spider man jumps horizontally, thus his velocity has no vertical component initially)

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g = 9.8 m/s²

Therefore,

100 m = (0 m/s)t + (0.5)(9.8 m/s²)t²

t² = (100 m)/(4.9 m/s²)

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t = 4.5 s

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s = vt

where,

s = x = horizontal distance covered = 10 m

v = V₀ₓ = Horizontal Component of Initial Velocity = Initial Velocity = ?

Therefore,

10 m = v(4.5 s)

v = 10 m/4.5 s

<u>v = 2.22 m/s</u>

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