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Dafna1 [17]
3 years ago
15

Consider the sections of two circuits illustrated above. Select True or False for all statements. After connecting c and d to a

battery, the current through R3 always equals the current through R4. Rcd is always less than or equal to R3. After connecting a and b to a battery, the voltage across R1 always equals the voltage across R2. Rab is always less than or equal to R1.
Physics
1 answer:
Basile [38]3 years ago
5 0

Answer:

Follows are the solution to the given question:

Explanation:

In this question the missing file of the circuit is not be which is defined in attached file please find it.

In Option 1, this statement is true because the current is on R_3 \  and \ R_4, that is the same.

In option 2, this statement is false because Rcd=R_3+R_4 therefore it implies that Rcd is always larger then R_3.

In option 3,  this statement is true because the voltage of R_1 \ and \ R_2 is always equal.

In option 4, this statement is true because Rab= \frac{1}{(\frac{1}{R1}+\frac{1}{R2})}=\frac{R1R2}{(R1+R2)}. \frac{R2}{(R1+R2)}is always smaller then 1 therefore,R_1 \times (\frac{R2}{(R1+R2)}) is always equal to R1.

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Answer:

a = 0.8 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:

∑F = m*a

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Now using Newton's second law.

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Learn more about white dwarfs here: brainly.com/question/24873876

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