Orient the semi-circle arc such that it is symmetric with respect to the y-axis. Now, by symmetry, the electric field in the x-direction cancels to zero. So the only thing of interest is the electric field in the y-direction.
dEy=kp/r^2*sin(a) where k is coulombs constant p is the charge density r is the radius of the arc and a is the angular position of each point on the arc (ranging from 0 to pi. Integrating this renders 2kq/(pi*r^3). Where k is 9*10^9, q is 9.8 uC r is .093 m
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Explanation:
It is given that,
The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:
Where,
x is in meters and t is in sec
We know that,
Velocity,
(a) i. t = 2 s
At t = 4 s
(b) Acceleration,
Pu t = 3 s in above equation
So,
Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²
Answer:
divide by mass and volume
Explanation:
density=mass/volume
or in symbols:p=m/v
Answer:
35 kg
Explanation: Newton's Second Law of Motion reinterpreted as or