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Zepler [3.9K]
3 years ago
13

An aerosol can contains 350.mL of gas at a pressure of 5.00 atm. What would be the volume of the gas at 2.00atm?

Chemistry
1 answer:
Margaret [11]3 years ago
8 0

Answer:

<h2>875 mL</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{350 \times 5}{2}  =  \frac{1750}{2}  \\

We have the final answer as

<h3>875 mL</h3>

Hope this helps you

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C. is the best choice
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Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. The balanced chemical equation
Rufina [12.5K]

The mass formed in a chemical reaction is given by stoichiometry law in balanced chemical equation. The mass of silver produced in the reaction is 107. 9 g.

<h3>What is the stoichiometric law?</h3>

The stoichiometric law states that in a balanced chemical equation, the stoichiometric coefficient describes the moles of each compound in a chemical reaction.

The balanced chemical equation for the reaction is:

\rm Cu\;+\;2\;AgNO_3\;\rightarrow\;Cu(NO_3)_2\;+\;2\;Ag

From the balanced chemical equation, 1 moles of copper results in 2 moles of silver.

Moles in terms of mass can be given as:

\rm Moles=\dfrac{Mass}{Molar\;mass}

Thus, moles of 31. 75 grams copper is:

\rm Cu=\dfrac{ 31. 75 }{63.5}\;mol\\ Cu=0.5 mol

The moles of Ag produced can be given from stoichiometric law as:

\rm 1\;mol\;Cu=2\;mol\;Ag\\0.5 \;mol\;Cu=0.5\;\times\;2\;mol\;Ag\\0.5\;mol\;Cu=1\;mol\;Ag

The moles of Ag produced is 1 mol.

The mass of a mole of element is equivalent to the molar mass. Thus, the mass of Ag produced in the reaction is 107. 9 g. Hence, option B is correct.

Learn more about stoichiometric law, here:

brainly.com/question/6907332

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2 years ago
Which has more calories: table sugar or aspartame?
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Explain what happens when two light waves traveling from the same direction of displacement meet.
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3 years ago
Calculate the mass, in grams, of Avogadro's number of fluorine atoms. Enter your answer in the provided box. I g/mol
juin [17]

Answer:

Every substance, whether an element or a compound that contains Avogadro's number, is said to form a mole of it. Therefore for the fluorine atoms that form the Avogadro number we say that we have one mole of fluorine atoms and this weighs 19 g, so 19 g/mol

Explanation:

You can search the F in the Periodic Table where you have the molar mass, 19 g/mol but if you don't have a Periodic Table you can calculate like this:

1 atom of F weighs 19 Da (unified atomic mass unit) and 1 Da is 1,661 x10*-24 g, so try to apply a rule of three, twice.

1 Da ........... 1,661x10*-24 g

19 Da .......... x

x= (19 Da . 1,661x10*-24 g ) / 1 Da = 3,1559x10*-23 g

1 atom F ..............  3,1559x10*-23 g

6,022x10*23 atoms F ............. x

X= (6,022x10*23 atoms F . 3,1559x10*-23 g) / 1 atom F = 19.0048 g

3 0
3 years ago
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