All categories

3 years ago

It takes Venus 225 days to orbit the sun. If the Earth-sun distance is 1.5 × 10^11 m, what

Physics

1 answer:

loris [4]3 years ago

6 0

Answer:

Distance between Venus and Sun is 1.0864x10^11 m

Explanation:

Data

T1 (Total time taken by earth to rotate around sun)=365 days

T2 (Total time taken by venus to rotate around sun)=225 days

R1 (Radius b/w Sun and earth)=1.5x10^11m

R2(Distance between Venus and Sun)=?

Solution

Apply Kepler Law

(R2)^3/(R1)^3=(T1)^2/(T2)^2

(R2)^3/(1.5x10^11)^3=(225^2)/(365^2)

R2=1.0864x10^11m

You might be interested in

An air-track glider attached to a spring oscillates between the 14.0 cm mark and the 71.0 cm mark on the track. The glider compl

horsena [70]

Answer:

A = 2,8333 s

Explanation:

El periodo es definido como el tiene que toma de dar una oscilación.

En este caso realiza varias osicilacion por lo cual debemos encontrar el promedio del perdono.

T = t/n

calculemos

A = 34,0/ 12,0

A = 2,8333 s

6 0

2 years ago

How are some types of collisions different from others?

lyudmila [28]

There are two general types of collisions, inelastic and elastic.
Inelastic collisions occur when two objects collide but neither of them bounce away from each other.
Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering)

3 0

2 years ago

Astronaut Sarah leaves Earth in a spaceship at a speed of 0.280c relative to Earth. Sarah's destination is a star-system 12.5 li

Usimov [2.4K]

Answer:

L= 12 light years

Explanation:

for length dilation we use the formula

$L=L_0\sqrt{1-\frac{v^2}{c^2} }$

now calculating Lo

Lo = 12.5×365×24×3600×3×10^8

= 1.183×10^17 m

now putting the values of v and Lo in the above equation we get

$L=1.183\times10^{17}\sqrt{1-\frac{0.28c^2}{c^2} }$

= 1.136×10^17 m

L= $= \frac{1.136\times10^{17}}{365\times24\times3600\times3\times10^8}$ m

so L= 12 light years

8 0

3 years ago

A wave with a greater amplitude will transfer . . . . \

BabaBlast [244]

less mass is more mass but less energy in more mass. less mass has more energy

6 0

3 years ago

A 1.20 kg water balloon will break if it experiences more than 530 N of force. Your 'friend' whips the water balloon toward you

soldi70 [24.7K]

Answer:

t = 0.029s

Explanation:

In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

$F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}$ (1)

m: mass of the water balloon = 1.20kg

Δv: change in the speed of the balloon = v2 - v1

v2: final speed = 0m/s (the balloon stops in my hands)

v1: initial speed = 13.0m/s

Δt: interaction time = ?

The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:

$|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s$

The interaction time to avoid that the water balloon breaks is 0.029s

5 0

3 years ago