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Naya [18.7K]
3 years ago
7

It takes Venus 225 days to orbit the sun. If the Earth-sun distance is 1.5 × 10^11 m, what

Physics
1 answer:
loris [4]3 years ago
6 0

Answer:

Distance between Venus and Sun is 1.0864x10^11 m

Explanation:

Data

T1 (Total time taken by earth to rotate around sun)=365 days

T2 (Total time taken by venus to rotate around sun)=225 days

R1 (Radius b/w Sun and earth)=1.5x10^11m

R2(Distance between Venus and Sun)=?

Solution

Apply Kepler Law

(R2)^3/(R1)^3=(T1)^2/(T2)^2

(R2)^3/(1.5x10^11)^3=(225^2)/(365^2)

R2=1.0864x10^11m

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Describe succinctly the relationship between how far a galaxy is from us (its distance), versus how fast it is moving.
Eva8 [605]

Answer:

Distance is directly proportional to the velocity

Explanation:

In 1929, Edwin Hubble's wrote an article that talked about relationship between the distance and recession speed/velocity of galaxies which led to what is known as the Hubble Law. This law states that galaxies are moving away from the earth at velocities proportional to their distances.

Thus is written as;

v = H_o•d

Where;

v is velocity

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H_o is Hubble's constant rate of cosmic expansion.

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3 years ago
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Radda [10]

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Explanation:

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3 years ago
At what rate must a cylindrical spaceship rotate if occupants are to experience simulated gravity of 0.50 gg? Assume the spacesh
Svetradugi [14.3K]

Answer:

The time needed is T  = 16.8 s

Explanation:

From the question we are told that

      The magnitude of the stimulated acceleration due gravity is  a  =  0.5 g

        The diameter of the spaceship is  d =  35m

       

Generally the force acting on the spaceship is  

       F  =  ma

Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

      F  = \frac{mv^2}{r}

Thus  

       ma  =  \frac{mv^2}{r}

=>    \frac{v^2}{r}  =  a

      Generally the speed of this spaceship is mathematically represented as

      v =  \frac{2 \pi}{T}

=>    v^2  =   [\frac{2\pi}{T}] ^2

=>     \frac{\frac{4\pi^2 r^2}{T^2} }{r}  = 0.5g

=>       \frac{4 \pi^2 r }{T^2} =  0.5 g

=>         T  = \sqrt{ \frac{4\pi^2 r}{0.5g}}

substituting values

          T  = \sqrt{ \frac{4* (3.142)^2 *(35)}{0.5 * 9.8}}

         T  = 16.8 s

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heya mate

the planet Jupiter has most gravity due to its size

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Julie wants to know if adding calcium fertilizer to tomato plants will help prevent a disease of tomato plants called blossom-en
Ksivusya [100]
It's not true.

The crucial principle for a scientific experiment is to keep only ONE variable at a time.

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