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3 years ago

When a wave strikes a solid barrier it behaves like a basketball hitting a backboard this wave behavior years called?

Physics

2 answers:

nignag [31]3 years ago

8 0

The answer is Reflection

Alex73 [517]3 years ago

6 0

This property of a wave is reflection.
Reflection of a wave is the process by which waves such as light, sound , infrared, or radio waves, hits and object and bounces off it. It is the change in direction of a wave front at an interface between two different media so that the wavelength returns into the medium of origin. From the law of reflection for a specular reflection the angle at which the wave is incident on the surface is equal to the angle at which it is reflected.

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All these are properties except

marin [14]

Amethyst... because it's silicon dioxide

3 0

3 years ago

Escribo dentro del paréntesis la letra (F) si el enunciado es falso o (V) si el enunciado es verdadero. Fundamento si mi elecció

KatRina [158]

Answer:

El primero es (V) y el segundo es(f)

4 0

3 years ago

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. We replace one of the objects with an

Alona [7]

Answer:

F'= 4F/9

Explanation:

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

$F=\dfrac{kQ^2}{r^2}$ ...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

$F'=\dfrac{kQ\times 4Q}{(3r)^2}\\\\F'=\dfrac{4kQ^2}{9r^2}$ .....(2)

Dividing equation (1) and (2), we get :

$\dfrac{F}{F'}=\dfrac{\dfrac{kQ^2}{r^2}}{\dfrac{4kQ^2}{9r^2}}\\\\\dfrac{F}{F'}=\dfrac{kQ^2}{r^2}\times \dfrac{9r^2}{4kQ^2}\\\\\dfrac{F}{F'}=\dfrac{9}{4}\\\\F'=\dfrac{4F}{9}$

Hence, the correct option is (d) i.e. " 4F/9"

7 0

3 years ago

In a belly-flop diving contest, the winner is the diver who makes the biggest splash upon hitting the water. the size

ad-work [718]

The second diver have to leap to make a competitive splash by 4.08 m high.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

PE = mgh

where, g = 9.81 m/s²

Given is the diver jumps from a 3.00-m platform. one diver has a mass of 136 kg and simply steps off the platform. another diver has a mass of 100 kg and leaps upward from the platform.

The potential energy of the first diver must be equal to the second diver.

P.E₁ = P.E₂

m₁gh₁ = m₂gh₂

Substitute the vales, we have

136 x 3 = 100 x h₂

h₂ = ₂4.08 m

Thus, the second diver need to leap by 4.08 m high.

Learn more about potential energy.

brainly.com/question/24284560

#SPJ1

7 0

2 years ago

I just want to shift to another country to learn like London so who can tell me the progress

scoray [572]

Answer:

by shift do you mean travel

Explanation:

3 0

3 years ago