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Levart [38]
3 years ago
12

A ball rolls onto the path of your car as you drive down a quiet neighborhood street. to avoid hitting the child that runs to re

trieve the ball, you apply your brakes for 1.20 s. the car slows down from 15.0 m/s to 9.00 m/s. the mass of the car is 1290 kg. (b) how far did the car move while braking?
Physics
1 answer:
KengaRu [80]3 years ago
5 0

Since the acceleration of car is uniform so the distance traveled by car while brakes are applied is given by

d = \frac{v_f + v_i}{2}*t

given that

v_f = 9 m/s

v_i = 15 m/s

t = 1.20 s

now plug in all data in above formula

d = \frac{15 + 9}{2} * 1.2

d = 14.4 m

so car will cover 14.4 m distance while it apply brakes

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A 2.0-kg projectile is fired with initial velocity components v0x = 30 m/s and v0y = 40 m/s from a point on the Earth's surface.
EleoNora [17]

(a) The kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.

(b) The work done  in firing the projectile is 2,500 J.

<h3>Kinetic energy of the projectile at maximum height</h3>

The kinetic energy of the projectile when it reaches the highest point in its trajectory is calculated as follows;

K.E = ¹/₂mv₀ₓ²

where;

  • m is mass of the projectile
  • v₀ₓ is the initial horizontal component of the velocity at maximum height

<u>Note:</u> At maximum height the final vertical velocity is zero and the final horizontal velocity is equal to the initial horizontal velocity.

K.E = (0.5)(2)(30²)

K.E = 900 J

<h3>Work done in firing the projectile</h3>

Based on the principle of conservation of energy, the work done in firing the projectile is equal to the initial kinetic energy of the projectile.

W = K.E(i) = ¹/₂mv²

where;

  • v is the resultant velocity

v = √(30² + 40²)

v = 50 m/s

W = (0.5)(2)(50²)

W = 2,500 J

Thus, the kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.

The work done  in firing the projectile is 2,500 J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

5 0
1 year ago
What is the current
Art [367]

Answer:

2.5mA

Explanation:

In the picture.

I think it's a clear.

8 0
3 years ago
Malia has developed Type II Diabetes. When she eats, her body
AlladinOne [14]

Answer:

The correct option is c.

Explanation:

Metabolism is a sum of anabolic and catabolic reactions. The body's inability to produce/synthesize enough insulin is the cause of type II diabetes. Generally, metabolism is the process in which most compounds (proteins, carbohydrates and lipids) are produced (anabolism) or broken down (catabolism) in the body. Insulin is a protein that can be produced in less amount due to metabolic disorder in the body.

Maria's disease means she already has an exponentially high amount of blood sugar against the required insulin to balance it out, hence the disease already slowed down her rate of metabolism (catabolism) of blood sugar EXCEPT she decides to increase of metabolism by medication and exercise.

3 0
3 years ago
A ball rolls from 10 m to -25 m in 2.5 seconds. What was<br> its average velocity?<br> (Units = m/s)
marissa [1.9K]

Answer:

v = -14 m/s

Explanation:

Given that,

Initial location of the ball, X₁ = 10 m

Final position of the ball,  X₂ = -25 m

Time taken to travel is, t = 2.5 s

The average velocity of the ball is given by the formula,

                       V = X₂ - X₁ / t     m/s

Substituting the values in the above equation,

                       V = -25 - 10 / 2.5

                          = -14 m/s

The negative sign in the velocity indicates that ball rolls in the opposite direction.

Hence, the average velocity of the ball is  v = -14 m/s

8 0
3 years ago
What is the wavelength of radar waves with the frequency of 6.0 x 10 ^10 Hz?
Serjik [45]

Yes yes multiply hurry up

8 0
3 years ago
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