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3 years ago

How does Ben and Jerry's total displacement compare to their distance traveled?

Physics

1 answer:

Sladkaya [172]3 years ago

5 0

Answer:comparing the total displacement and tota distance covered by Ben Jerry.

Explanation:

Total distance travelled by both is;

m+n=z

Total displacement of both is;

x+y=z

Therefore;

comparing equation 1 and 2;

x+y=m+n

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Atmospheric pressure decreases with increment in height.<br> give reason

jekas [21]

Answer:

pressure=height × density×acc due to gravity

pressire is directly proportional to height hence it decreses with decrease in height

here air column height is measured upside down so decreases witn increment

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3 years ago

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What did Thomson’s model of the atom include that Dalton’s model did not have?

astraxan [27]

Answer: Option (d) is the correct answer.

Explanation:

Dalton's model of atom states that every matter is made up of atoms and these atoms are indivisible in nature.

On the other hand, Thomson's model of atom states that there are small particles present in an atom that has positive or negative charges.

Thomson's model of atom is also known as plum pudding model where negatively charged particles are represented by plum and positively charged particles are represented by pudding.

Thus, we can conclude that Thomson’s model of the atom include smaller particles that Dalton’s model did not have.

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3 years ago

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Supercells are updrafts that may cause which of the following?

ale4655 [162]

just for anyone looking for the answer i just took the test and the answer is tornadoes

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3 years ago

A negative ion of charge -2e is located at the origin and a second negative ion of charge -3e is located nearby at x = 3.8 nm ,

Rus_ich [418]

Answer:

$\vec{F}_{21}=-5.63\times 10^{-11}N\\\\\vec{F}_{21}=\\$

Explanation:

Given that

$Q_1 = -2e\, C\\\\Q_2=-3e\,C\\\\x= 3.8 \times 10^{-9}\,m\\\\y= 3.2 \times 10^{-9}\,m\\\\r=\sqrt{x^2+y^2}\\\\r= 4.96\times 10^{-9} m\\$

As both charges are negative so there exist force of repulsion in direction as shown in figure.

$F_{12}=\frac{kQ_1Q_2}{r^2}\\\\F_{12}= \frac{(9\times 10^9)(6)(1.602\times 10^{-19})^2}{(4.96\times 10^{-9})^2}\\\\F_{12}=5.63\times 10^{-11}N$

Angle at which force F12 is acting is

$\theta=tan^{-1}\frac{3.2}{3.8}\\\\\theta=tan^{-1}\frac{y}{x}\\\\\theta= 40.1^o$

$F_{x}=F_{12}cos\theta\\\\F_{x}=(5.63\times 10^{-11})cos(40.1)\\\\F_{x}=4.306\times 10^{-11}N\\\\F_{y}=F_{12}sin\theta\\\\F_{y}=(5.63\times 10^{-11})sin(40.1)\\\\F_{y}=3.62\times 10^{-11}N\\\\$

$\vec{F}_{12}=\vec{F}_{x}+\vec{F}_y\\\\\vec{F}_{12}=4.30\times 10^{-11}\,\hat{i} + 3.62\times 10^{-11}\,\hat{j}\\\\\vec{F}_{12}=$

Force exerted on charge -2e is equal in magnitude to F12 but is in opposite direction

$F_{21}=-5.63\times 10^{-11}N$

$\vec{F}_{21}=$

7 0

3 years ago

A police car moving at 36.0 m/s is chasing a speeding motorist traveling at 30.0 m/s. The police car has a siren that emits soun

maxonik [38]

Answer:

The frequency heard by the motorist is 4313.2 Hz.

Explanation:

let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.

because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:

f1 = [(v + v2/(v - v1))]×(f2)

= [( 343 + 30)/(343 - 36)]×(3550)

= 4313.2 Hz

Therefore, the frequency heard by the motorist is 4313.2 Hz.

5 0

3 years ago