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3 years ago

Prefix and suffix for hydrology

Physics

1 answer:

Tju [1.3M]3 years ago

8 0

Prefix: Hydro

Suffix: Logy

I hope I helped you! <3

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a painting in an art gallery has height h and is hung so that its lower edge is a distance d above the eye of an observer. How f

harkovskaia [24]

Solution:

With reference to Fig. 1

Let 'x' be the distance from the wall

Then for $\Delta$ DAC:

$tan\theta = \frac{d}{x}$

⇒ $\theta = tan^{-1} \frac{d}{x}$

Now for the $\Delta$ BAC:

$tan\theta = \frac{d + h}{x}$

⇒ $\theta = tan^{-1} \frac{d + h}{x}$

Now, differentiating w.r.t x:

$\frac{d\theta }{dx} = \frac{d}{dx}[tan^{-1} \frac{d + h}{x} - tan^{-1} \frac{d}{x}]$

For maximum angle, $\frac{d\theta }{dx}$ = 0

Now,

0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} - tan^{-1} \frac{d}{x}][/tex]

0 = $\frac{-(d + h)}{(d + h)^{2} + x^{2}} -\frac{-d}{x^{2} + d^{2}}$

$\frac{-(d + h)}{(d + h)^{2} + x^{2}} = \frac{{d}{x^{2} + d^{2}}$

After solving the above eqn, we get

x = $\sqrt{\frac{d}{d + h}}$

The observer should stand at a distance equal to x = $\sqrt{\frac{d}{d + h}}$

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3 years ago

Earth that are large enough to be detected by radar

Novosadov [1.4K]

Answer:

I don't now sorry HHHAHAH GOOD LUCK

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3 years ago

A balloon is filled with 1500 mL of air at a pressure of 5 atm. What is the pressure of the balloon if the volume is changed to

Eva8 [605]

Answer:

xcfdbrtbfcgctr dsvrd

Explanation:

ds vfg g cd fg

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Chuge%5Ctextbf%7BHelp%7D%20" id="TexFormula1" title=" \huge\textbf{Help} " alt=" \huge\te

Aleks [24]

Answer:

Geometrical optics, or ray optics, describes the propagation of light in terms of "rays" which travel in straight lines, and whose paths are governed by the laws of reflection and refraction at interfaces between different media.

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2 years ago

Read 2 more answers

Circular Motion A 650-kg car moving at 8.5 m/s takes a turn around a circle with a radius of 48.0 m. Determine the acceleration

ollegr [7]

Answer:

Explanation:

The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.

$a=\frac{v^2}{r}$ and filling in

$a=\frac{(8.5)^2}{48.0}$ and we need 2 significant digits in our answer. That means that

a = 1.5 m/sec²

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3 years ago