All categories

2 years ago

Please answer 100 points Divide. 6 from 3/5 10 30 20 15

Mathematics

2 answers:

love history [14]2 years ago

7 0

Answer:

The numbers in 6 divided by 3/5 are labeled below:

6 = whole number

3 = numerator

5 = denominator

To make it a fraction form answer, you multiply the whole number by the denominator and make the result the new numerator. The old numerator becomes the new denominator:

6 x 5

Thus, the answer to 6 divided by 3/5 in fraction form is:

To make the answer to 6 divided by 3/5 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

30 / 3 = 10

The answer is rounded to the nearest two decimal points if necessary.

30/3 can be simplified to 10/1.

10/1 is an improper fraction and should be written as 10.Step-by-step explanation:

almond37 [142]2 years ago

5 0

Answer:

Step-by-step explanation:

What is 6 divided by 3/56 ÷ 3 5. The trick to working out 6 divided by 3/5 is similar to the method we use to work out dividing a fraction by a whole number. ... 6 x 5 3 = 30 3. So, the answer to the question "what is 6 divided by 3/5?" ... 30 3. ... 10 1. ... 10 1 = 10.

You might be interested in

Please help me with this one. I need help right away.

lana66690 [7]

b(1 -2) i just too the test

6 0

3 years ago

If backpack is discounted 10% ib sale for $37.80 what is the original price

taurus [48]

the answer is $34. 36 if I understood your question correctly.

8 0

3 years ago

Latoya has b decks of cards . Each deck has 52 cards in it , what is the expression for the total numbers of cards latoya has

Lerok [7]

Answer:

52b

Step-by-step explanation:

She has 52 cards per deck, and b decks.

This means she has 52b cards.

How this works:

For 1 deck, she has 52 cards, or 52×1 cards.

For 2 decks, she has 104 cards, or 52×1 cards.

For 5 decks, she has 260 cards, or 52×5 cards.

For 10 decks, she has 520 cards, or 52×10 cards.

Therefore, for b decks, she has 52×b, or 52b cards.

**This content involves writing algebraic expressions, which you may wish to revise. I'm always happy to help!

6 0

3 years ago

1. A test-tube has a diameter of 3cm. How many turns would a piece of thread of length

Alex Ar [27]

So if we think of a test tube, it looks sort of like a cylinder. This means that its cross-section would be a circle. To find out how many turns a piece of thread would make around the test tube, we need to find the circumference of the test tube, then divide the length of the string by the circumference.

Step 1) Find the circumference

C = pi x diameter

C = 3.14 x 3

C = 9.42

Step 2) Divide the length of the string by the circumference

90.42 / 9.42 = 9.5987

The string would make approximately 9.60 turns around the test tube.

Hope this helps!! :)

6 0

3 years ago

Not sure what to do here can someone please help

kumpel [21]

Answer:

x = 2

Step-by-step explanation:

These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.

<h3>Squaring</h3>

The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.

$\sqrt{x+2}+1=\sqrt{3x+3}\qquad\text{given}\\\\(x+2)+2\sqrt{x+2}+1=3x+3\qquad\text{square both sides}\\\\2\sqrt{x+2}=(3x+3)-(x+3)=2x\qquad\text{isolate the root term}\\\\x+2=x^2\qquad\text{divide by 2, square both sides}\\\\x^2-x-2=0\qquad\text{write in standard form}\\\\(x-2)(x+1)=0\qquad\text{factor}$

The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.

x = -1: √(-1+2) +1 = √(3(-1)+3) ⇒ 1+1 = 0 . . . . not true

x = 2: √(2+2) +1 = √(3(2) +3) ⇒ 2 +1 = 3 . . . . true . . . x = 2 is the solution

<h3>Substitution</h3>

Another way to solve this is using substitution for one of the radicals. We choose ...

$u=\sqrt{x+2}\qquad\text{requires $u\ge0$}\\\\u^2-2=x\qquad\text{solve for x}\\\\u+1=\sqrt{3(u^2-2)+3}\qquad\text{substitute for x in the original equation}\\\\(u+1)^2=3u^2-3\qquad\text{square both sides, simplify a little}\\\\2u^2-2u-4=0\qquad\text{subtract $(u+1)^2$}\\\\2(u-2)(u+1)=0\qquad\text{factor}$

Solutions to this equation are ...

u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution

The value of x is ...

x = u² -2 = 2² -2

x = 2 . . . . the solution to the equation

_____

<em>Additional comment</em>

Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.

6 0

2 years ago