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2 years ago

Integer, 12 ft above sea level ???

Mathematics

2 answers:

kozerog [31]2 years ago

7 0

It’s -12 since 12 is already a positive number it has to be opposite so it will have to be a negative number.

Alekssandra [29.7K]2 years ago

7 0

Answer:

Your answer is -12

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How many hundreds tens and ones have 423

Gnom [1K]

Four hundreds two tens and three ones

7 0

3 years ago

Read 2 more answers

There are 850 Douglas fir and Ponderosa pine trees in a section of forest bought by Karamazov Logging Co. The company paid an av

ki77a [65]

Answer:

350 Douglas fir, 500 Ponderosa pine

Step-by-step explanation:

Let f = the number of fir trees

and p = the number of pine trees.

Then, we have two conditions:

(1) f + p = 850

(2) 300f + 225p = 217 500

(3) p = 850 -f Subtracted f from each side of (1)

(4) 300f + 225(850 - f) = 217 500 Substituted (3) into (3)

300f + 191 250 - 225f = 217 500 Distributed 225

75f + 191 250 = 217 500 Distributed the 7

75f = 26 250 Subtracted 191 250 each side

(5) f = 350

350 + p = 850 Substituted (5) into (1)

p = 500 Subtracted 350 from each side

The company bought 350 fir trees and 500 pine trees.

Check:

(1) 350 + 500 = 850 (2) 300 × 350 + 225 × 500 = 217 500

850 = 850 105 000 + 112 500 = 217 500

217 500 = 217 500

OK.

8 0

3 years ago

Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)

TEA [102]

Answer:

solution,

$a. \: x(x + 2) \\ \: \: = x \times x + 2 \times x \\ \: \: = {x}^{2} + 2x$

$b . \: x(2x - 5) \\ \: = x \times 2x - x \times 5 \\ \: \: = 2 {x}^{2} - 5x$

$c. \: 2x(3x + 4) \\ \: = 2x \times 3x + 2x \times 4 \\ \: \: = 6 {x}^{2} + 8x$

$d. \: 6x(x - 2) \\ \: \: = 6x \times x - 6x \times 2 \\ \: \: = 6 {x}^{2} - 12x$

Hope this helps...

Good luck on your assignment..

4 0

2 years ago

Triangles P Q R and S T U are shown. Angles P R Q and T S U are right angles. The length of P Q is 20, the length of Q R is 16,

dimaraw [331]

Answer:

$\angle P$

Step-by-step explanation:

Given

$\triangle PRQ = \triangle TSU = 90^o$

$PQ = 20$ $QR = 16$ $PR = 12$

$ST = 30$ $TU = 34$ $SU = 16$

<em>See attachment</em>

Required

Which sine of angle is equivalent to $\frac{4}{5}$

Considering $\triangle PQR$

We have:

$\sin(P) = \frac{QR}{PQ}$ --- i.e. opposite/hypotenuse

So, we have:

$\sin(P) = \frac{16}{20}$

Divide by 4

$\sin(P) = \frac{4}{5}$

Hence:

$\angle P$ is correct

7 0

2 years ago

Three dressers are places side by side. One dresser is 5 feet 11 inches wide, another is 5 feet 6 inches wide, and the third is

Sidana [21]

5'-11" + 5'-6" + 5'-9" [add feet, then add inches]
= 15'+(11+6+9)"=15'+26"=15'+2'+2"
=17'-2"

4 0

2 years ago