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The heavy atom count of a casein molecule is 143 I believe
Answer:
Sorry i don't know the answer
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buy if you don't mind then i want to ask something
<u>Whi</u><u>ch</u><u> class</u><u> </u><u>ques</u><u>tion</u><u> </u><u>is</u><u> </u><u>thi</u><u>s</u><u>?</u>
Answer:
0.0794 L
Explanation:
An experiment requires 62.7 g of ethyl alcohol. The density of ethyl alcohol is 0.790 g/mL. The volume, in milliliters, corresponding to 62.7 g of ethyl alcohol is:
62.7 g × (1 mL/0.790 g) = 79.4 mL
1 liter is equal to 1000 milliliters. The volume, in liters, corresponding to 79.4 mL is:
79.4 mL × (1 L/ 1000 mL) = 0.0794 L