- Pressure = 5000 Pa
- Contact Area = 0.04 m^2
- Acceleration due to gravity = 9.8 m/s^2
- Let the force be F.
- We know, Force = Pressure × Contact Area
- Therefore, Force = 5000 Pa × 0.04 m/s^2
- or, Force = 200 N
- We know, force = mass × acceleration
- Therefore, mass = force ÷ acceleration
- or, mass = 200 N ÷ 9.8 m/s^2 = 20.4 Kg
<u>Answer</u><u>:</u>
<u>2</u><u>0</u><u>.</u><u>4</u><u> </u><u>Kg</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
b) n = 1 to n = 4.
Explanation:
a ) n = 4 to n = 1 transition represents release of energy because transition is from high energy orbit to low energy orbit.
Similarly c) n = 2 to n = 1 represents release of energy because transition is from high energy to low energy orbit.
d ) n = 1 to n = 3 is also energy absorbing transition but amount of energy absorbed is less as compared with option b) transition .
So the correct option is b)
Answer:
Its resistance decreases
Explanation:
The resistance of a wire is directly proportional to the length of the wire and inversely proportional to the cross sectional area of the wire.
Mathematically,
R1 =¶L1/A1... (1)
R1= ¶L1/{Πd²/4}
R1= 4¶L1/Πd²
where;
¶ is the constant of proportionality which is the resistivity of the material
L is the length of the wire
A is the cross sectional area
A1 = Πd²/4
If the length is quadrupled and its diameter tripled
The new length L2 will be 4L1
New area A2 = Π(3d)²/4 = 9Πd²/4
The resistance will become
R2 = ¶(4L1)/{9Πd²/4}
R2 = 4¶L1×4/9Πd²
R2 = 16¶L1/9Πd²... (2)
R2/R1 = 16¶L1/9Πd²÷4¶L1/Πd²
R2/R1 = 16¶L1/9Πd²×Πd²/4¶L1
R2/R1 = 16/9×1/4
R2/R1 = 16/36
R2/R1 = 4/9
R2 = 4/9R1
This shows that the resistance of the wire decreases
