Answer:
The tension in the part of the cord attached to the textbook is 6.58 N.
Explanation:
Given that,
Mass of textbook = 2.09 kg
Diameter = 0.190 m
Mass of hanging book = 3.08 kg
Distance = 1.26 m
Time interval = 0.800 s
Suppose,we need to calculate the tension in the part of the cord attached to the textbook
We need to calculate the acceleration
Using equation of motion
Put the value into the formula
We need to calculate the tension
When the book is moving with acceleration
Using formula of tension
Hence, The tension in the part of the cord attached to the textbook is 6.58 N.