Question

A textbook of mass 2.09 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190 m, to a hanging book with mass 3.08 kg. The system is released from rest, and the books are observed to move a distance 1.26 m over a time interval of 0.800 s.

Answer 1

Answer:

The tension in the part of the cord attached to the textbook is 6.58 N.

Explanation:

Given that,

Mass of textbook = 2.09 kg

Diameter = 0.190 m

Mass of hanging book = 3.08 kg

Distance = 1.26 m

Time interval = 0.800 s

Suppose,we need to calculate the tension in the part of the cord attached to the textbook

We need to calculate the acceleration

Using equation of motion

$y=ut+\dfrac{1}{2}at^2$

$a=\dfrac{2y}{t^2}$

Put the value into the formula

$a=\dfrac{2\times1.26}{0.800}$

$a=3.15\ m/s^2$

We need to calculate the tension

When the book is moving with acceleration

Using formula of tension

$T=ma$

$T=2.09\times3.15$

$T=6.58\ N$

Hence, The tension in the part of the cord attached to the textbook is 6.58 N.