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kotegsom [21]
3 years ago
8

Rectangular prism has a height of 3cm, a width of 7 cm, and a length of 5 cm. What is it's volume?

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
6 0
Volume= length•width•height

V=5•7•3

V= 105cm^3
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Conduct metric Titration of H_2(SO_4) and Ba(OH)_2 Write an equation (including states of matter) for the reaction between H_2(S
meriva

Answer:

a) H₂SO₄ + Ba(OH)₂ ⇄ BaSO₄(s) + 2 H₂O(l)

b) H₂SO₄, H⁺, HSO₄⁻, SO₄²⁻. H₂O, H⁺, OH⁻.

c) H⁺, HSO₄⁻, SO₄²⁻

d) As the titration takes place, reaction [1] proceeds to the right. The conductivity of the solution decreases because the amount of H⁺, HSO₄⁻, SO₄²⁻ decreases. The formed solid is barium sulfate BaSO₄. Since BaSO₄ is very insoluble, the main responsible for conductivity are still H⁺, HSO₄⁻ and SO₄²⁻,

e) At the equivalence point equivalent amounts of H₂SO₄ and Ba(OH)₂ react. The conducting species are Ba²⁺, SO₄²⁻, H⁺ and OH⁻.

f) After the equivalence point there is an excess of Ba(OH)₂. The ions Ba²⁺ and OH⁻ are responsible for the increase in the conductivity, being the major conducting species.

Explanation:

a) Write an equation (including states of matter) for the reaction between H₂SO₄ and Ba(OH)₂.

The <em>balanced equation</em> is:

H₂SO₄ + Ba(OH)₂ ⇄ BaSO₄(s) + 2 H₂O(l)   [1]

b) At the very start of the titration, before any titrant has been added to the beaker, what is present in the solution?

In the beginning there is H₂SO₄ and the ions that come from its <em>dissociation reactions</em>: H⁺, HSO₄⁻, SO₄²⁻. There is also H₂O and a very small amount of H⁺ and OH⁻ coming from its <em>ionization</em>.

H₂SO₄(aq) ⇄ H⁺(aq) + HSO₄⁻(aq)

HSO₄⁻(aq) ⇄ H⁺(aq) + SO₄²⁻(aq)

H₂O(l)  ⇄ H⁺(aq) + OH⁻(aq)

c) What is the conducting species in this initial solution?

The main responsible for conductivity are the <em>ions</em> coming from H₂SO₄: H⁺, HSO₄⁻, SO₄²⁻.

d) Describe what happens as titrant is added to the beaker. Why does the conductivity of the solution decrease? What is the identity of the solid formed? What is the conducting species present in the beaker?

As the titration takes place, reaction [1] proceeds to the right. The conductivity of the solution decreases because the amount of H⁺, HSO₄⁻, SO₄²⁻ decreases. The formed solid is barium sulfate BaSO₄. Since BaSO₄ is very insoluble, the main responsible for conductivity are still H⁺, HSO₄⁻ and SO₄²⁻,

e) What happens when the conductivity value reaches its minimum value (which is designated as the equivalence point for this type of titration)? What is the conducting species in the beaker?

At the <em>equivalence point</em> equivalent amounts of H₂SO₄ and Ba(OH)₂ react. Only BaSO₄ and H₂O are present, and since they are <em>weak electrolytes</em>, there is a small amount of ions to conduct electricity. The conducting species are Ba²⁺ and SO₄²⁻ coming from BaSO₄ and H⁺ and OH⁻ coming from H₂O.

f) Describe what happens at additional titrant is added past the equivalence point. Why does the conductivity of the solution increase? What is the conducting species present in the beaker?

After the equivalence point there is an excess of Ba(OH)₂. The ions Ba²⁺ and OH⁻ are responsible for the increase in the conductivity, being the major conducting species.

7 0
3 years ago
A solid, pure substance containing just carbon and hydrogen is found to contain 35.8g of carbon and 3.72 g of hydrogen. how many
Igoryamba

Answer:

            4.36 g of Carbon

Solution:

Step 1: Calculate the %age of Carbon in given Solid as;

                        Mass of Carbon  =  35.8 g

                        Mass of Hydrogen  =  3.72

                        Total Mass  =  35.8 g + 3.72  =  39.52 g

                        %age of Carbon  =  (35.8 g ÷ 39.52 g) × 100

                        %age of carbon  =  90.58 %

Step 2: Calculate grams of Carbon in 4.82 g of given solid as;

                        Mass of Carbon  =  4.82 g × (90.58 ÷ 100)

                        Mass of Carbon  =  4.36 g

3 0
3 years ago
Identify the decomposition reaction. 2nh3 + h2so4 ⟶ (nh4)2so4 2nabr + ca(oh)2 ⟶ cabr2 + 2naoh 2 no2 ⟶ 2 o2 + n2 3pb + 2h3po4 ⟶ 3
TEA [102]

A decomposition reaction should look like

A ------> B +C+...

It has to have only one reactant and several products.

2 NO2 ⟶ 2 O2 + N2

7 0
3 years ago
Read 2 more answers
1. a) Binary ionic and binary molecular compounds have what two things that are similar in their composition? (b) What is one wa
kherson [118]
Binary compounds consist of only two distinct elements, regardless of whether the compound is ionic or molecular. Water is a binary compound, as are calcium chloride, ammonia, and potassium iodide. 

<span>An ionic binary compound consists of cations of one element and anions of another. KI is an ionic binary compound, composed of K cations and I anions. </span>

<span>A molecular binary compound does not consist of discrete ions, but of molecules. H2O is molecular, as is NH3.</span>
7 0
2 years ago
Oxygen is important in the oxidation of glucose because it ____________________________. Oxygen is important in the oxidation of
Vlad [161]

can be oxidized to form carbon dioxide

Explanation:

Oxygen is important in the oxidation of glucose because it can be oxidized to form carbon dioxide. Oxidation of glucose involves the reaction of oxygen with glucose in a process called respiration. This gives a product of water, carbon dioxide and energy which is stored as ATP.

  • Oxidation involves the addition of oxygen.
  • Any specie that undergoes oxidation, is a reducing agent and it is said to be oxidized.
  • Oxygen is oxidized to form carbon dioxide and water.

Learn more:

Respiration and photosynthesis brainly.com/question/3437832

#learnwithBrainly

3 0
3 years ago
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