Answer:

Explanation:
Hello there!
In this case, given the Henderson-Hasselbach equation, it is possible for us to compute the pH by firstly computing the concentration of the acid and the conjugate base; for this purpose we assume that the volume of the total solution is 0.025 L and the molar mass of the sodium base is 234 - 1 + 23 = 256 g/mol as one H is replaced by the Na:

And the concentrations are:
![[acid]=0.000855mol/0.025L=0.0342M](https://tex.z-dn.net/?f=%5Bacid%5D%3D0.000855mol%2F0.025L%3D0.0342M)
![[base]=0.000781mol/0.025L=0.0312M](https://tex.z-dn.net/?f=%5Bbase%5D%3D0.000781mol%2F0.025L%3D0.0312M)
Then, considering that the Ka of this acid is 2.5x10⁻⁵, we obtain for the pH:

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Answer:

Explanation:
Hello,
The six-carbon benzene ring contains two types of bonds: C-C and C-H bonds, that are
-hybridized σ bonds, and the six π bonds that form the aromatic ring. The σ bonds form from one
orbital and two
orbitals from each carbon, which then bond the carbon to the two carbons on either side and the carbon's single hydrogen. The remaining
orbital from each carbon atom sticks out above and below the plane of the ring; these
orbitals overlap sideways, rather than lengthwise, to form the aromatic π bond system.
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Answer:
Answers below (just some ethics)
Explanation:
Bad= Earthquake activity causing damage in a major city.
Bad= Producing and emitting smog from a smokestack.
Good= Planting native bushes to help control erosion.
Good= Volcanic eruption resulting in the formation of an island.
Answer:
1.004×10²²
Explanation:
The molar mass of carbon is 12 g/mol
which means that:
<u>1 mole of carbon atoms has a mass of 12 grams.</u>
Since, diamond is a allotrope of carbon.
Mass of 1.00-carat diamond in grams is:
1.00 carat = 0.200 g
<u>
Since, 1 mole of C contains 6.022×10²³ atoms of C</u>
So,
12 grams contains 6.022×10²³ atoms of C
1 gram contains 6.022×10²³/ 12 atoms of C
0.200 gram contains (6.022×10²³/ 12)×0.200 atoms of C
Thus,
<u>1 carat diamond contains 1.004×10²² atoms of C.</u>
Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ
Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.
The formula used to calculate the heat of the reaction can be expressed as follows:
Q = mcΔT
where:
- Q = quantity of heat transfer
- m = mass
- c = specific heat of water = 4.18 kJ/g °C (constant)
- ΔT = change in temparature
From the information given:
- The initial temperature (T₁) = 25° C
- The final temperature (T₂) = 91.5° C
∴
The change in temperature i.e. ΔT = T₂ - T₁
ΔT = 91.5° C - 25° C
ΔT = 66.5° C
The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³

= 0.05 moles
- Since the molar mass of CuSO₄ = 159.609 g/mol
Then;
Using the relation:

By crossing multiplying;
mass of CuSO₄ = number of moles of CuSO₄ × molar mass of CuSO₄
mass of CuSO₄ = 0.05 moles × 159.609 g/moles
mass of CuSO₄ = 7.9805 grams
∴
Using the formula from above:
Q = mcΔT
Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C
Q = 2218.34 kJ
Therefore, we can conclude that the heat of the reaction is 2218.34 kJ
Learn more about the chemical reaction here:
brainly.com/question/20250226?referrer=searchResults