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LenaWriter [7]
3 years ago
6

How much heat must be transferred to 100.0g of water to change its temperature by 35° C?

Chemistry
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

14700J

Explanation:

From the question given, the following were obtained:

M = 100g

ΔT = 35° C

C = 4.2J/g °C

Q=?

The heat transferred can calculated for by using the following equation

Q = MCΔT

Q = 100 x 4.2 x 35

Q= 14700J

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The taste of acid is sour​
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Explanation:

also the taste of salt is sour.

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Not enough air is pumped into an inflatable life raft to make completely filled out the atm pressure is 14.7psi what is the pres
sasho [114]
If you do not inflate the life raft to make completely filled out, as long as you do not press or squeeze  the life raft, the air inside it will be in equilibrium with the air outside the raft, and so the pressure inside the life raft will be the same atmospheric pressure, 14.7 psi.

Note that when the raft is swollen, if you punch it, the air will leave from it which means that the pressure inside is greater than the atmospheric pressure.
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A series of chemicals were added to some AgNO3(aq). NaCl(aq) was added first to the silver nitrate solution to produce a precipi
OLEGan [10]

Answer:

First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of HNO_{3}.

Explanation:

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Reaction: Ag^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)

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Reaction: AgCl(s)+2NH_{3}(aq.)\rightarrow [Ag(NH_{3})_{2}]^{+}(aq.)+ Cl^{-}(aq.)

In presence of HNO_{3}, [Ag(NH_{3})_{2}]^{+} complex gets destroyed and free Cl^{-} again reacts with free Ag^{+} to produce insoluble AgCl

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4 0
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34g aluminum are combined with 39g chlorine gas which is the limiting reactant
vampirchik [111]

The limiting reactant is chlorine (Cl2).

<u>Explanation</u>:

Limiting reactant is the amount of product formed which gets limited by the reagent without continuing it.

        2 Al + 3 Cl2 ==> 2 AlCl3  represents the balanced equation.

Number of moles Al present = 34 g Al x 1 mole Al / 26.98 g

                                                = 1.260 g moles of Al

Number of moles Cl2 present = 39 g Cl2 x 1 mole Cl2 / 35.45 g

                                                  = 1.10 g moles of Cl2

Dividing each reactant by it's coefficient in the balanced equation obtains:

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The reactant which produces a lesser amount of product is called as limiting reactant.

Here the Limiting reactant is Cl2.

6 0
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