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3 years ago

If two of a triangle's angles measure 42 and 48 how would you classify that triangle? Write acute,obtuse,right

Mathematics

2 answers:

sertanlavr [38]3 years ago

5 0

I think it is acute because below 90 is acute above 90 is obtuse and exactly 90 is right

iris [78.8K]3 years ago

5 0

Third angle = 180º - 42º - 48º = 90º = Right

Triangle ABC Type:
By angles: Right (A=90°) <= This!
By sides: Scalene (a≠b≠c≠a)

Draw it: http://triancal.esy.es/?B=42°&C=48º

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The figure is made up of a cylinder and a cone.

Gnoma [55]

Answer:

51*pi or 160.221

Step-by-step explanation:

total volume = volume of a cone + volume of a cylinder

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total volume = 1/3 * pi * 3^2 * 5 + pi * 3^2 * 4

total volume = 51*pi = 160.221

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3 years ago

Show work ! please !!!!!!

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Sin A = opp/hyp = 4/5

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Tan A = opp/adj = 4/3

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You can just plug that into your graphing calculator, just make sure the degree mode is on.

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2 years ago

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nikdorinn [45]

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Step-by-step explanation:

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2 years ago

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3 years ago

Read 2 more answers

Find the second derivative of 2x^3-3y^2=8

Umnica [9.8K]

Answer:

$\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

Step-by-step explanation:

Find the first implicit derivative using implicit differentiation

$2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}$

Use the substitution of dy/dx to find the second derivative (d²y/dx²)

$\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

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2 years ago