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Licemer1 [7]
3 years ago
9

382 3/10 - 191 87/100=

Mathematics
2 answers:
ipn [44]3 years ago
7 0
(382 3/10) - (191 87/100) = <span>190.43
hope it helps</span>
frosja888 [35]3 years ago
5 0
382  \frac{3}{10}  - 191  \frac{87}{100} =(382 + \frac{3}{10} ) - (191 + \frac{87}{100}) =\\\\=382 + \frac{30}{100} -191- \frac{87}{100} =382  -191+ \frac{30}{100}- \frac{87}{100} =\\\\=191+ \frac{30}{100}- \frac{87}{100} =190+ \frac{100}{100}+ \frac{30}{100}- \frac{87}{100} =\\\\=190+\frac{130}{100}- \frac{87}{100} =190+\frac{43}{100}=190\frac{43}{100}\\\\\\382  \frac{3}{10}  - 191  \frac{87}{100} =382.3  - 191.87 =382.3  - 191-0.87 =191.3-0.87=\\\\=190+1.3-0.87=190+0.43=190.43
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C = 4+0. 10t what is the charge to rent a paddle boat for 20 minutes?
Blababa [14]
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5 0
2 years ago
A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses
laila [671]

Answer:

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P(E) = ?

Event X = Football player misses the first pass

P(X) = 0.4

Event Y = Football player misses just after he first miss

P(Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P(E) = P(X).P(Y)

P(E) = 0.4*0.2

P(E) = 0.08

4 0
3 years ago
Which of the following represents the relationship between the circumference, c, and diameter, d, of any circle?
Usimov [2.4K]

Given:

Circumference of a circle = C

Diameter of a circle = d

To find:

The relationship between the circumference, c, and diameter, d, of any circle.

Solution:

We know that, circumference of a circle is

C=2\pi r

It can be written as

C=(2r)\pi

C=d\pi         [\because d=2r]

On dividing both sides by d, we get

\dfrac{C}{d}=\pi

Therefore, the correct option is (F).

6 0
2 years ago
Factor Completely.<br> 12k^2-16k-60
faltersainse [42]

Answer:

4(k - 3)(3k + 5)

Step-by-step explanation:

Given

12k² - 16k - 60 ← factor out 4 from each term

= 4(3k² - 4k - 15) ← factor the quadratic

Consider the factors of the product of the coefficient of the k² term and the constant term which sum to give the coefficient of the k term

product = 3 × - 15 = - 45 , sum = - 4

Factors are - 9 and + 5

Use these factors to split the middle term

3k² - 9k + 5k - 15 → ( factor the first/second and third/fourth terms

= 3k(k - 3) + 5(k - 3) ← factor out (k - 3)

= (k - 3)(3k + 5)

Hence

12k² - 16k - 60 = 4(k - 3)(3k + 5) ← in factored form

8 0
3 years ago
Read 2 more answers
Which route must use all of the vertices of a vertex-edge graph? (Check all that apply.)
zlopas [31]

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4 0
3 years ago
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