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Licemer1 [7]
3 years ago
9

382 3/10 - 191 87/100=

Mathematics
2 answers:
ipn [44]3 years ago
7 0
(382 3/10) - (191 87/100) = <span>190.43
hope it helps</span>
frosja888 [35]3 years ago
5 0
382  \frac{3}{10}  - 191  \frac{87}{100} =(382 + \frac{3}{10} ) - (191 + \frac{87}{100}) =\\\\=382 + \frac{30}{100} -191- \frac{87}{100} =382  -191+ \frac{30}{100}- \frac{87}{100} =\\\\=191+ \frac{30}{100}- \frac{87}{100} =190+ \frac{100}{100}+ \frac{30}{100}- \frac{87}{100} =\\\\=190+\frac{130}{100}- \frac{87}{100} =190+\frac{43}{100}=190\frac{43}{100}\\\\\\382  \frac{3}{10}  - 191  \frac{87}{100} =382.3  - 191.87 =382.3  - 191-0.87 =191.3-0.87=\\\\=190+1.3-0.87=190+0.43=190.43
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Answer:

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Step-by-step explanation:

to do a dilation you keep the angle measure of the angles of the shape the same while multiplying the length of the sides by the scale factor

5 0
3 years ago
Y=2x+1 x+y=7 pls help meeeeeeeee
Gala2k [10]

Answer:

y=2,\:x=\frac{5}{2}

Step-by-step explanation:

\begin{bmatrix}x+1\cdot \:x+y=7\\ y=2\end{bmatrix}

x+1· x+2=7

Simplify x+1· x+2:    2x+2x+1· x+2

Add similar elements: x+1· x=2x=2x+2

2x+2=7[ 2x+2=7 ]

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2x+2−2=7−2

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5 0
3 years ago
Read 2 more answers
Which explains whether or not the values in the table represent a direct variation?
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4 0
3 years ago
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

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P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
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Salsk061 [2.6K]

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Step-by-step explanation:

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7 0
3 years ago
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