Convert the Haworth projection of the carbohydrate below into its corresponding Fischer projection (in the standard format with
the most oxidized carbon at the top) and chair conformation (correctly drawing equatorial and axial bonds) of the opposite anomer. Then answer the questions in the problem. Upload a photo of your answer as a jpeg file. If we can't read it, we can't grade it!
1 answer:
Answer:
See explaination
Explanation:
H O / I MOH the OH da Anomer My nequatorial bovel SOH niematerial and CH2OH Yr axial boud - H o H o . H (Auro) 2 flip . note: 1)Fischer projection : L- Sugar ( OH group is in the left side ) at C-5 carbon (bottom most chiral center )
In the Haworth projection given above in the qsn it is Beta anomer( -CH2OH & C-OH are in same side i.e. Cis to each other ). It is a L -sugar .
I omitted C2 -H bond (axial ) in the chair conformation of alpha anomer.
See attachment for further solution
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Answer:
The standard enthalpy of formation of this isomer of is -220.1 kJ/mol.
Explanation:
The given chemical reaction is as follows.
The expression for the entropy change for the reaction is as follows.
Substitute the all values in the entropy change expression.
Therefore, The standard enthalpy of formation of this isomer of is -220.1 kJ/mol.