Answer : To calculate the standard molar enthalpy of complete combustion of liquid ethanol can be done by using the formula given below;
Now, the enthalpies of the elements in their standard state is zero always.
So the
Here we can avoid the heat of enthalpy of oxygen,carbon dioxide and water as they exists in their standard states.
So the
=
Because it has no <span> stereogenic carbon centres.</span>
No 11) one mole of Zn and two mole of HCL to get one mole of ZnCl and one mole of H2.
no 12) one mole of Mg and two mole of AgNO3 to get one mole of Mg(No3)2 and two mole of Ag.
no 13) one mole of CaCl2 and two mole AgNO3 to get two mole of AgCl and one mole of Ca(NO3)2.
no 14) two mole of Na3PO4 and three mole of BaCL2 to get one mole of Ba3(PO4)2 and six mole of NaCl.
no 15) two mole of NH4Cl and one mole of Ba(OH)2 to get one mole of BaCL2,two mole of NH3 and two mole of H2O.(am not much sure about this).
no 16) one mole of Na2CO3 and two mole of HCL to get two mole of NaCl,one mole of H2O and one mole of CO2.
no 17) one mole of K3PO4 and three mole of AgNO3 to get three mole of KNO3 and one mole of AgPO4.
Answer: He is modeling the condensation process in the water cycle.
Answer:
P1V1 = P2V2
(1.5 atm)(5.6 L) = (x)(4.8 L) x = 1.8 atm
