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2 years ago

What are the most common elements in the canyon

1 answer:

4 0

The most common element found in crayons would be carbon and hydrogen. Since crayons are made up of paraffin and other chemical pigments. Paraffin is wax like material, which is derived from petroleum, wood, or coal. All three contain large amounts of hydrocarbons, which is carbon and hydrogen compounds.

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A green shirt looks green to you because

musickatia [10]

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A green shirt looks green because light reflects off of the green shirt. ... Visible light on the electromagnetic spectrum is found in between infrared waves and ultraviolet waves.

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3 years ago

What is the correct sequence of events in the food chain?

Veseljchak [2.6K]

I believe it is the fourth choice because the producer would use sunlight to make food, then the next choice fhat has anything to do with the producer is [D]. if i’m wrong i’m sorry but I believe that would be the write anwser.

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2 years ago

Which base is the strongest for the given [H+]?

AURORKA [14]

The answer is 10-12. The relationship of pH and [H+] is pH = -lg[H+]. And the higher pH, the stronger base is. So the strongest base has the lowest concentration of H+.

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3 years ago

A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.

irga5000 [103]

Answer:

1. pH = 1.23.

2. $H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)$

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

$H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+$

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

$pH=pKa+log(\frac{[base]}{[acid]} )$

Whereas the pKa is:

$pKa=-log(Ka)=-log(5.90x10^{-2})=1.23$

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

$pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23$

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

$n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol$

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

$H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)$

Which is also shown in net ionic notation.

Best regards!

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2 years ago

In the nucleus, there are 36 protons and 36 neutrons

antoniya [11.8K]

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2 years ago