Question

Calculate the tension in a horizontal leather string that whirls a 0.5-kg rock in a circle of radius 1.25 m when it moves at 8 m/s while being slung around a slinger's head.

Answer 1

Answer:

Tension in the leather string is T = 25.6 N

Explanation:

As we know that belt is revolving in horizontal circle

So the tension force in the belt will provide the required centripetal force

So we will have

$T = \frac{mv^2}{L}$

now we have

$v = 8 m/s$

L = 1.25 m

m = 0.5 kg

so we have

$T = \frac{0.5(8^2)}{1.25}$

$T = 25.6 N$