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AysviL [449]
3 years ago
13

What is the net force acting on the piano

Physics
1 answer:
CaHeK987 [17]3 years ago
5 0

answer: 500 net force

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kap26 [50]

Answer:

friction, conduction and induction

Explanation:

Had it in class I had it correct hope this helps.

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3 years ago
A jet airliner moving initially at 504 mph (with respect to the ground) to the east moves into a region where the wind is blowin
adelina 88 [10]

Answer

given,

intial velocity = 504 mph

wind speed = 219 mph

at an angle of 29◦

from the data

 The resultant velocity =

V = V_x \hat{i} + V_y\hat{j}

 V = (504 + 219 cos 29^0 ) \hat{i} +(219 sin 29^0 )\hat{j}

 V = 695.54\hat{i} + 106.17 \hat{j}

the magnitude of velocity

V = \sqrt{695.54^2+106.17^2}

V = 703.59 m/s

direction

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8 0
3 years ago
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student
IRINA_888 [86]

Answer:

0.063 Kg

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 10 Hz

Spring constant (K) = 250 N/m

Mass (m) =?

Next, we shall determine the period of oscillation. This can be obtained as follow:

Frequency (f) = 10 Hz

Period (T) =?

T = 1/f

T = 1/10

T = 0.1 s

Finally, we shall determine the mass of the spring. This can be obtained as follow:

Spring constant (K) = 250 N/m

Period (T) = 0.1 s

Pi (π) = 3.14

Mass (m) =?

T = 2π√(m/K)

0.1 = 2 × 3.14 × √(m/250)

0.1 = 6.28 × √(m/250)

Divide both side by 6.28

0.1 / 6.28 = √(m/250)

Take the square of both side.

(0.1 / 6.28)² = m/250

Cross multiply

m = (0.1 / 6.28)² × 250

m = 0.063 Kg

Therefore, the mass of the spring is 0.063 Kg.

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3 years ago
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