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sergij07 [2.7K]
3 years ago
13

A gold puck has a mass of 12 kg and a velocity of 5i – 4j m/s prior to a collision with a stationary blue puck whose mass is 18

kg. After an elastic collision, the blue puck has a velocity of 2i – 2j m/s. What is the velocity of the gold puck after the collision?
A. 2i –j m/s
B. 3i –j m/s
C. 2i – 2j m/s
D. 3i – 2j m/s
Physics
1 answer:
Ugo [173]3 years ago
6 0

Answer:

Explanation:D

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Read 2 more answers
QUESTION 7
ryzh [129]

Answer:

<em>The force required is 3,104 N</em>

Explanation:

<u>Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+at

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

\displaystyle a=\frac{0-20.4}{7.4}

a=-2.757\ m/s^2

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

F = 1,126\ kg * 2.757\ m/s^2

F= 3,104 N

The force required is 3,104 N

6 0
2 years ago
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