Question

Two loudspeakers in a plane, 5.0m apart, are playing the same frequency. If you stand 14.0m in front of the plane of the speakers, centered between them, you hear a sound of maximum intensity. As you walk parallel to the plane of the speakers, staying 14.0m in front of them, you first hear a minimum of sound intensity when you are directly in front of one of the speakers.-What is the frequency of the sound? Assume a sound speed of 340 m/s.

Answer 1

Answer:

f= 196.3 Hz

Explanation:

The path difference between two waves given as

$\Delta = \sqrt{14^2+5^2}\ -14$

Δ = 0.866 m

We know that to hear minimum intensity the path difference given as

Δ = λ/2

λ = 2Δ

We know that

C= f λ

Now by pitting the values

340 = 2 x 0.866 x f

f= 196.3 Hz