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ycow [4]
3 years ago
13

A bag contains 7 red marbles, 3 blue marbles and 2 green. If two marbles are drawn out of the bag, what is the probability, to t

he nearest 1000th, that both marbles drawn will be blue?
Mathematics
1 answer:
Setler [38]3 years ago
5 0

Answer:

0.0455

Step-by-step explanation:

<u>The formula for calculator probability is </u>

# of favorable outcomes / # of possible outcomes

<u>The total number of marbles in the bag: </u>

7+3+2=12

<u>Probability of the first marble being blue:</u>

3/12

<u>Probability of the second marble being blue:</u>

2/11 -- 2 because only 2 blue marbles left after drawing the first one out, 11 because after taking the first marble out, we have 11 marbles left in the bag

<u>Formula for both events happening:</u>

p(A and B) = p(A) * p(B)

In this problem,

A = first one blue

B = second one blue

<u>Probability that if two marbles are drawn out of the bag, both are blue:</u>

3/12 x 2/11 = 0.045454

<u>Rounded answer:</u>

0.0455 (or 4.55%)

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An = a1 + (n - 1)(d)
Where a1 is the first term and d is the common difference.
First find d, the common difference.
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