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Vsevolod [243]
3 years ago
8

15 POINTS!!

Physics
1 answer:
sleet_krkn [62]3 years ago
8 0

Hello  !

<u>Quelle affirmation est correcte à propos de la substance inconnue?  </u>

<u />

<u>Son point de fusion est de 17 ° C.  </u>

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A 95 N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 N · m. What is the angle (assumed to
o-na [289]

Answer:

angle = 18.40 degree

Explanation:

given data

force = 95 N

distance = 0.50 m

torque = 15 N · m

to find out

angle between the wrench handle and the direction of the applied force

solution

we will apply here torque equation that is express as

torque =  distance × force × sin(θ)   ...................1

put here value we will get angle that is

15 = 0.50 × 95 × sin(θ)

sin(θ) = 0.315789

θ = 18.40 degree

6 0
3 years ago
Read 2 more answers
Can carrying an object be said to be doing work on that object?
Schach [20]

Answer:

Only if that object is being moved while carried

Explanation:

Work = Force • distance travelled

While holding an object would need force equal to that objects mass multiplied by 9.8, if it hasn't moved, then no work is done.

if you were to carry the object and have it travel some distance, then work would be done on that object.

7 0
3 years ago
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Describe the history of magnetism​
Anestetic [448]

Answer:

Explanation:

it is a force generated in matter by the motion of electrons within its atoms.

3 0
3 years ago
How much voltage is found in a line restance of 10ohms and a current of 20 amps
Aleks04 [339]

Hello,

According to Ohm's Law,

V=IR

where v=Voltage, I=Current, and R= resistance.

So, if we take a line resistance of 10 ohms, and a current of 20 amps we get

200 Volts.

Hope this helped.

5 0
4 years ago
An oscillating block-spring system has a mechanical energyof 1.00 J and amplitude of 10.0 cm and a maximum speed of 1.20m/s. Fin
Debora [2.8K]

Answer:

Explanation:

Given

Mechanical Energy of Spring-Block system is 1 J

Maximum Amplitude is A=10 cm

maximum speed v_{max}=1.2 m/s

Suppose x=A\sin \omega tbe general equation of motion of spring-mass system

where A=max amplitude

\omega=Natural frequency of oscillation

t=time

v_{max}=A\omega =1.2

0.1\cdot \omega =1.2

\omega =12 rad/s

maximum kinetic Energy must be equal to total Mechanical Energy when spring is un deformed i.e. at starting Position

\frac{1}{2}mv_{max}^2=1

m=\frac{2}{1.2^2}=\frac{2}{1.44}=1.38 kg

Also \omegais also given by

\omega =\sqrt{\frac{k}{m}}

k=\omega ^2\cdot m

where k= spring constant

k=12^2\cdot 1.38

k=200 N/m

             

6 0
4 years ago
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