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3 years ago

Which process is represented by the PV diagram?

Physics

1 answer:

Reika [66]3 years ago

3 0

Hi!

The answer would be A. Isobaric Process

<h3>Explanation:</h3>

Isobaric process is a process where the pressure inside a system remains unchanged. In the Pressure Volume graph given, you can see that the pressure (y axis) remains constant with an increasing volume ( x axis). An example of this would be heating a container with a movable piston. Now, the degree of pressure is dependent on the frequency of collisions of particles inside a system on the walls. If this frequency changes, the pressure changes (proportionally). In our example, heating a container with a movable piston results in the particles inside the container to gain kinetic energy and move faster, meaning an increased frequency of collisions (higher pressure), but at the system time the increase in pressure results in the piston being pushed outwards, causing the volume of the container to increase. This results in decreased frequency of collision of the particles with the walls of the container (lesser pressure). This results in the a zero net effect on the pressure.

Hope this helps!

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If it requires 8.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

jenyasd209 [6]

Answer:

The amount of work done required to stretch spring by additional 4 cm is 64 J.

Explanation:

The energy used for stretching spring is given by the relation :

$E = \frac{1}{2}kx^{2}$ .......(1)

Here k is spring constant and x is the displacement of spring from its equilibrium position.

For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

$8 = \frac{1}{2}\timesk\times k \times(0.02)^{2}$

k = 4 x 10⁴ N/m

Energy needed to stretch a spring by 6.0 cm can be determine by the equation (1).

Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

$E = \frac{1}{2}\times4\times10^{4}\times (0.06)^{2}$

E = 72 J

But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :

E = ( 72 - 8 ) J = 64 J

7 0

3 years ago

How many charges are required to have an electric field

Liono4ka [1.6K]

One charge is enough in order to have an electric field.

In fact, every charge generates an electric field: for example, the electric field generated by a single point positive charge is radial, as shown in the attached figure. More complicate electric field configurations can be obtained adding charges or using more complicate charge distributions, but one charge is enough to have an electric field.

7 0

3 years ago

A water tank, full of water, has internal dimensions of 1 m x 2 m x 5 m. The density of water is 1000 kg/m³. The volume of the w

MatroZZZ [7]

Answer:

volume of water inside the tank is 10 cubic meter

Explanation:

As we know that the volume of total water inside the tank is given as

$V = L \times H \times W$

here we know that

L = length = 1 m

H = height = 2 m

W = width = 5 m

now we have

$V = 1 \times 2 \times 5$

$V = 10 m^3$

So volume of water inside the tank is 10 cubic meter

3 0

3 years ago

Help me ?? i need it by tomorrow

nignag [31]

It would help if you listed the needed vocabulary words.

7 0

3 years ago

Various singly-ionized atomic nuclei of the same speed are directed into a magnetic field in a mass spectrometerwhere they are d

ki77a [65]

Answer:

a) least mass

Explanation:

According to the Newton's first law of motion, more the mass of a body the greater is its inertia, and inertia is the tendency of a body to resist any change to its state of rest or uniform motion.

Greater is the mass of charge least is its deflection under the influence of magnetic field.

<em>This can be explained well by the mathematical equations relating the </em><em>centripetal force and the magnetic force</em><em> on a charged mass moving in a magnetic field perpendicular to the velocity:</em>

$m.\frac{v^2}{r} =q.v.B$

where:

m = mass of the charged particle

v = velocity of projection of the charged mass into the magnetic field

r = radius of curvature of path of charged mass under the magnetic force

q = magnitude of charge on the particle of mass 'm'

B = intensity of magnetic field normal to 'v'

$\Rightarrow v=\frac{q.B.r}{m}$

$\Rightarrow v\propto \frac{1}{m}$

i.e.

Speed of the charge is higher when its mass is lesser and according to the Fleming's left hand rule we known that the charge continuously faces a magnetic force while moving in the field.

& also,

$\Rightarrow m\propto \frac{1}{r}$

Which indicates that more is the mass of charge larger is the radius of its trajectory of motion which means lesser is its deviation.

6 0

3 years ago