Question

a force vector f has a magnitude of 12.0 n. it is oriented 60° to the left of the y ax what are its x and y components?

Answer 1

The  force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:

• v(x) =6 N
• v(y) = 10.39 N

To solve this exercise the formulas and procedures we will use are:

• v(x) = v * cosine (angle)
• v(y) = v * sine (angle).

Where:

• v= magnitude of the vector
• v(x) = component of the vector on the (x) axis
• v(y) = component of the vector on the (y) axis
• angle = angle

Information about the problem:

• angle = 60º
• v = 12.0 N
• v(x)= ?
• v(y)= ?

Applying the formula of the component of the vector in the (x) axis we have:

v(x) = v * cosine (angle).

v(x) = 12.0 N * cosine (60º)

v(x) =6 N

Applying the formula of the component of the vector in the (y) axis we have:

v(y) = v * sine (angle)

v(y) = 12.0 N * sine (60º)

v(y) = 10.39 N

What is a vector?

It can be said to be a straight line described by a point (a) and (b) that has direction and sense.

Learn more about vector at: brainly.com/question/2094736

#SPJ4