a force vector f has a magnitude of 12.0 n. it is oriented 60° to the left of the y ax what are its x and y components?
1 answer:
The force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:
- v(x) =6 N
- v(y) = 10.39 N
To solve this exercise the formulas and procedures we will use are:
- v(x) = v * cosine (angle)
- v(y) = v * sine (angle).
Where:
- v= magnitude of the vector
- v(x) = component of the vector on the (x) axis
- v(y) = component of the vector on the (y) axis
- angle = angle
Information about the problem:
- angle = 60º
- v = 12.0 N
- v(x)= ?
- v(y)= ?
Applying the formula of the component of the vector in the (x) axis we have:
v(x) = v * cosine (angle).
v(x) = 12.0 N * cosine (60º)
v(x) =6 N
Applying the formula of the component of the vector in the (y) axis we have:
v(y) = v * sine (angle)
v(y) = 12.0 N * sine (60º)
v(y) = 10.39 N
<h3>What is a vector?</h3>It can be said to be a straight line described by a point (a) and (b) that has direction and sense.
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Answer:
Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C
Explanation:
given,
surface charge (q) = 3.3 × 10⁻⁶ C
to calculate electric flux = ?
a) radius = 0.76 m
area of sphere = 4 π r²
electric flux =
electric flux =
flux = 0.373 × 10 ⁶ N m²/C
electric flux in the other two cases will also be same as electric flux is independent of area
so, Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C