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AlexFokin [52]
3 years ago
15

Electric Field of Ring of Charge A ring shaped charge has a radius of 0.250 meters and bears a total charge of +5.00 C What is t

he magnitude of the electric field along the axis of symmetry of the ring a distance of 0.500 meters from the center of the ring? ? A. 1.29 × 105 N/C 0 B. 1.67 × 105 N/C O C. 2.59 x 105 N/C ? D. 3.95 × 105 N/C
Physics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

6.44 × 10^10 N/C

Explanation:

Electric field due to the ring on its axis is given by

E = K q r / (r^2 + x^2)^3/2

Where r be the radius of ring and x be the distance of point from the centre of ring and q be the charge on ring.

r = 0.25 m, x = 0.5 m, q = 5 C

K = 9 × 10^9 Nm^2/C^2

E = 9 × 10^9 × 5 × 0.25 / (0.0625 + 0.25)^3/2

E = 6.44 × 10^10 N/C

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Taco Bell sells 6 Tacos for $9.00. Del Taco sells 4 tacos for $8.00. is a better deal, because it costs less per taco.
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Assume that the turntable deccelerated during time Δt before reaching the final angular velocity ( Δt is the time interval betwe
Zina [86]

Answer:

See below...

Explanation:

Let’s express ⟨α⟩ in terms of ωi , ωf , and Δt. and torque in terms of It , ωi , ωf , and Δt.

STEP 1.  

The rate of change of angular velocity is Angular acceleration.  

The net change in angular velocity is Average angular acceleration divided by the elapsed time.

⟨α⟩ = ω f −ω i/Δt

STEP 2.

Torque is assumed this way

          dω

   τ = I ----

           dt

.

⟨τ ⟩ = I t (ω f −ω i )/Δt

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3 years ago
Predict what happens when glucose levels are high in the humms body
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Glucose is blood sugar (hyperglycemia) comes from diabeties often, but can occur with other reasons, when glucose is to high someoenes sugar raises. Often this can lead to a diabetic coma, fatigue, vomiting, hospitalization, and even death if serious enough, from to high sugar. Many things can happen after this, and a lot are serious.

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5 0
3 years ago
A person pushes two boxes with a horizontal force F of magnitude of 100 N.
Monica [59]

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

  • m_A = 9\  kg

Mass of box B,

  • m_B = 2 \ kg

Horizontal force,

  • F_{app} = 100 \ N

From the Newton's law,

→ F_{app} = (\frac{F_{app}}{m_A+m_B} )a

or,

→      a = \frac{F_{app}}{(m_A+m_B)}

Bu substituting the values, we get

→         = \frac{100}{9+2}

→         = \frac{100}{11}

→         9.10 \ m/s^2

We can see that between the two boxes, the action-reaction pair exist.

then,

→ F_{action-reaction} = m_b \ a

→                          =2\times 9.10

→                          = 18.2 \ N (magnitude)

Thus the above solution is appropriate.

 

Learn more about the magnitude here:

brainly.com/question/13545862

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