Question

Electric Field of Ring of Charge A ring shaped charge has a radius of 0.250 meters and bears a total charge of +5.00 C What is the magnitude of the electric field along the axis of symmetry of the ring a distance of 0.500 meters from the center of the ring? ? A. 1.29 × 105 N/C 0 B. 1.67 × 105 N/C O C. 2.59 x 105 N/C ? D. 3.95 × 105 N/C

Answer 1

Answer:

6.44 × 10^10 N/C

Explanation:

Electric field due to the ring on its axis is given by

E = K q r / (r^2 + x^2)^3/2

Where r be the radius of ring and x be the distance of point from the centre of ring and q be the charge on ring.

r = 0.25 m, x = 0.5 m, q = 5 C

K = 9 × 10^9 Nm^2/C^2

E = 9 × 10^9 × 5 × 0.25 / (0.0625 + 0.25)^3/2

E = 6.44 × 10^10 N/C