How many significant figures are there in the number<br> 2.3409500?

How much energy is imparted to an electron as it flows through a 6 V battery from the positive to the negative terminal? Express

Hatshy [7]

The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge

Given values:
V = 6V, q = 1.6x10^-19C

Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ

8 0

3 years ago

Use the diagram below to answer the following question:

d1i1m1o1n [39]

Answer:

3.0 cm

Explanation:

We can solve this problem by using the mirror equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length of the mirror

p is the distance of the object from the mirror

q is the distance of the image from the mirror

In this problem we have:

f = 1.5 cm is the focal length of the mirror (positive for a concave mirror)

p = 3.0 cm is the distance of the object from the mirror

Therefore, the distance of the image is:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{1.5}-\frac{1}{3.0}=\frac{1}{3.0}\\\rightarrow q=3.0 cm$

And the positive sign means that the image is real.

(The second part of the exercise is just the description of the image of the first exercise).

5 0

2 years ago

Sound waves with frequency higher that 20,000 Hz are referred to as

Solnce55 [7]

<span>Sound waves with frequency higher that 20,000 Hz are referred to as "Ultrasonic"

Hope this helps!</span>

4 0

3 years ago

How are frequency and wave period related?

dedylja [7]

-- The unit of frequency is "per second" (Hz), which is [reciprocal time].

-- The unit of period is "second", which is [time].

Do you see where this is going ?

'Frequency' and 'period' are reciprocals of each other.

For any wave ...

Period = (1) / (frequency) .

Frequency = (1) / (period) .

6 0

3 years ago

While in a car at 4.47 meters per second a passenger drops a ball from a height of 0.70 meters above the top of a bucket how far

viktelen [127]

Answer:

1.7 m

Explanation:

$v_x$ = Velocity of ball in x direction = 4.47 m/s

$u_y$ = Velocity of ball in y direction = 0

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

t = Time taken

$s_y$ = Vertical displacement = 0.7 m

$s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.7=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{0.7\times 2}{9.81}}\\\Rightarrow t=0.38\ \text{s}$

Horizontal displacement is given by

$s_x=v_xt\\\Rightarrow s_x=4.47\times 0.38\\\Rightarrow s_x=1.7\ \text{m}$

The passenger should throw the ball 1.7 m in front of the bucket.

5 0

3 years ago

How many significant figures are there in the number 2.3409500?