Answer:
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.0518
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
In this question:
. So
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Answer:
Place the squares on the rectangle.
Step-by-step explanation:
Hello!
The area of the 1cm by 1cm square is 1 square cm.
We can solve for the area by placing multiple of those squares in the larger rectangle.
If we place it, we get 15 placed squares, with a total area of 15 square cm. This relies on the meaning of area, as we are simply measuring the number of square cm taken up by the object.
We would place 3 rows of 5 squares, representing a height of 3 cm (side length of 3 squares), and a length of 5 cm (side length go 4 squares).
This also proves the area formula A = L * W, as we multiple the side lengths to find the number of square units.
On the graph, we can see that when x=1, y=0.
But we don't even need to bother opening the attachment
and studying the graph !
In your question, you said that one point on the function is (1, 0) .
That means that when 'x' is 1, 'y' is zero. And there you are !
Answer:
kjh7563653 365385 36539y5 53nkddg dhdk djgd ghgkg d99 76 79
Step-by-step explanation:
Don't touch the center. It is already even.
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.
Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.
Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2
Join 3 to 4
Join 5 to 6
I think 3 is the minimum.
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