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Gelneren [198K]
3 years ago
8

An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti

l time 15.6s. What is the impulse experienced by the object?
Physics
1 answer:
shusha [124]3 years ago
3 0

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

I=F\Delta t

where:

I is the impulse

F is the force exerted on the object

\Delta t is the time during which the force is applied

For the object in this problem, we have

F=106 N (force applied)

\Delta t= 15.6 s (time interval)

Therefore, the impulse experienced by the object is:

I=(106)(15.6)=1654 kg m/s

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A car is traveling 20 m/s and slows down at a uniform rate. It stops in 6 seconds. How far has it traveled in this interval?
Scilla [17]

Answer:

Car travel a distance of 60.06 m in 6 sec

Explanation:

We have given initial velocity v = 20 m/sec

Time = 6 sec

As the car stops finally so final velocity v = 0

From the first equation of motion

v = u+at (as the car velocity is slows down means it is a case of deceleration)

So v = u-at

0=20-a\times 6

a=3.33m/sec^2

Now from second equation of motion s=ut-\frac{1}{2}at^2=20\times 6-\frac{1}{2}\times 3.33\times 6^2=60.06m

6 0
3 years ago
A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
Which describes what happens when a balloon is rubbed with a wool cloth?
777dan777 [17]
When a balloon is rubbed with a wool cloth, e<span>lectrons move from the atoms in the balloon to the atoms in the cloth, causing the cloth to have a negative charge. Therefore, the answer is B. Before they were rubbed together, they both had balanced charges. However, after rubbing them, the wool is left with the positive charge, and the balloon with the negative. This causes the atoms in the cloth to flow to the balloon, leaving the cloth with a negative charge.</span>
4 0
3 years ago
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State the law of conversation of momentum​
Sliva [168]
The total momentum before a collision is equal to the total momentum after the collision if no external forces act on the system.
Hope this helps
6 0
3 years ago
A squirrel is trying to locate some nuts he buried for the winter. He moves 4.3 m to the right of a stone and dogs unsuccessfull
krek1111 [17]

Answer:

The total displacement from the starting point is 1.5 m.

Explanation:

You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).

First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.

Second, it moves 6.3 m right, so the new distance is 9.5 m.

Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.

Summarizing, at the end the squirrel is 1.5 m from its starting point.

8 0
4 years ago
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