If 1mol ------- is ----------- 6,02×10²³
so x ------- is ----------- 1,39×10²⁴
Answer:
A. 0.0655 mol/L.
B. PbBr2.
C. Pb2+(aq) + Br- --> PbBr2(s).
Explanation:
Balanced equation of the reaction:
Pb(NO3)2(aq) + 2NaBr(aq) --> PbBr2(s) + 2NaNO3(aq)
A.
Number of moles
PbBr2
Molar mass = 207 + (80*2)
= 367 g/mol.
Moles = mass/molar mass
= 3.006/367
= 0.00819 mol.
Since 2 moles of NaBr reacted to form 1 mole of PbBr2. Therefore, moles of NaBr = 2*0.00819
= 0.01638 moles of NaBr.
Since, the ionic equation is
NaBr(aq) --> Na+(aq) + Br-(aq)
Since 1 moles of NaBr dissociation in solution to give 1 mole of Br-
Therefore, molar concentration of Br-
= 0.0164/0.25 L
= 0.0655 mol/L.
B.
PbBr2
C.
Pb(NO3)2(aq)--> Pb2+(aq) + 2No3^2-(aq)
2NaBr(aq) --> 2Na+(aq) + 2Br-(aq)
Net ionic equation:
Pb2+(aq) + 2Br- --> PbBr2(s)
<u>Answer:</u> The volume of the container is 
<u>Explanation:</u>
To calculate the volume of water, we use the equation given by ideal gas, which is:

or,

where,
P = pressure of container = 200 kPa
V = volume of container = ? L
m = Given mass of water = 2.61 kg = 2610 g (Conversion factor: 1kg = 1000 g)
M = Molar mass of water = 18 g/mol
R = Gas constant = 
T = temperature of container = ![200^oC=[200+273]K=473K](https://tex.z-dn.net/?f=200%5EoC%3D%5B200%2B273%5DK%3D473K)
Putting values in above equation, we get:

Converting this into cubic meter, we use the conversion factor:

So, 

Hence, the volume of the container is 
Answer:
The answer should be 2 because to balance the equation you should have to change to equation to this; 2Al + 3Br2 => 2AlBr3, so that there is a total of 2 Aluminums and 6 Bromiums on either side of the equation.
Explanation: