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Elena L [17]
3 years ago
12

What is the formula of a compound formed between phosphorus (P) and barium (Ba)?

Chemistry
2 answers:
satela [25.4K]3 years ago
6 0
Ba3P2


______________________________________
Assoli18 [71]3 years ago
4 0
I believe this would be Ba3P2 (the numbers are subscripts; meant to be little)
I am taking Honors Chem so I hope this helps!!
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B

Explanation:

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Which two changes would make this reaction product-favored? 3H2 + N2 ⇄ 2NH3 + energy  A. Decreasing the pressure  B. Increasin
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Read 2 more answers
How much energy is required to boil 65 grams of 100°C water<br> And then heat the steam to 150°C?
Artyom0805 [142]

Answer:

13598 J

Explanation:

Q = m × c × ∆T

Where;

Q = amount of energy (J)

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

m = 65g, specific heat capacity of water = 4.184J/g°C, initial temperature= 100°C, final temperature = 150°C

Q = 65 × 4.184 × (150 - 100)

Q = 271.96 × 50

Q = 13598 J

Hence, 13598 J of energy is required to boil 65 grams of 100°C water and then heat the steam to 150°C.

8 0
3 years ago
Carbon dioxide gas is collected at 27.0(degrees)C in an evacuated flask with a measured volume of 30.0L. When all the gas has be
White raven [17]

Answer:

Moles of carbon dioxide gas is 0.584 moles.

Mass of 0.584 moles of carbon dioxide gas is 25.7  g

Explanation:

Using ideal gas equation

PV = nRT

where,

P = Pressure of gas = 0.480 atm

V = Volume of gas = 30.0 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 27°C = 300.15 K

Putting values in above equation, we get:

(0.480 atm)\times 30.0 L=n\times (0.0821L.atm/mol.K)\times 300.15K\\\\n=0.5844 mol\approx 0.584

Moles of carbon dioxide gas = 0.584 moles

Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7  g

5 0
3 years ago
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