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Amiraneli [1.4K]
3 years ago
12

True or False

Chemistry
1 answer:
Darina [25.2K]3 years ago
3 0
The answer would be true
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Find [OH-], pH and pOH of a solution where [H+]=7.2x10-2M
Mamont248 [21]
pH: 1.14266750357
pOH: 12.8573324964
[H+]: 0.072
[OH-]: 1.38888888889E-13 acid
4 0
2 years ago
ENTER THE COEFFICIENTS DIRECTLY FROM THE BALANCED CHEMICAL EQUATION. do not reduce to lowest terms. for example: if 3 moles H2 r
dlinn [17]

Answer:

The coefficients are 2 for H₂O and 1 for Ca(OH)₂.

Explanation:

Let's consider the following reaction.

Ca(OH)₂(aq) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂O(l)

According to the balanced equation, the molar ratio of H₂O to Ca(OH)₂ is 2:1. Using this conversion factor, we have the following proportion:

moles Ca(OH)₂. (2 mol H₂O ÷ 1 mol Ca(OH)₂) = moles H₂O

4 0
3 years ago
A 2.3 kg object has 15 ) of kinetic energy. Calculate its speed.
chubhunter [2.5K]

Answer:

<h3>The answer is option D</h3>

Explanation:

To find the speed given the kinetic energy and mass we use the formula

v =  \sqrt{ \frac{2KE}{m} }  \\

where

m is the mass

v is the speed

From the question

KE = 15 J

m = 2.3 kg

We have

v =  \sqrt{ \frac{2 \times 15}{2.3} }  =  \sqrt{ \frac{30}{2.3} }  \\  = 3.61157559...

We have the final answer as

<h3>3.6 m/s</h3>

Hope this helps you

7 0
3 years ago
How many nanoseconds are there in one minute?
umka21 [38]
1 minute equals 6e+10 nanoseconds.
I hope this helped! :>
3 0
3 years ago
How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i
vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

<em></em>

I hope it helps!

7 0
3 years ago
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