I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.
Answer:
false is the answer because it was around in the 1880's
Explanation:
I hope this helped
<span>When t=0, v=0, d=0
When t=tf, v=41m/s, d=3.5m
We have 2 formulas – the ones corresponding to uniformly accelerated linear movement:
vf=a*t+vo
d=(1/2)*a*t^2+vo*t
Let’s put the data in the formulas:
41m/s=a*t+0=a*t
3.5m=(1/2)*a*t^2+0*t=1/2*a*t^2
You can use a variety of methods to find t and a. I will choose substitution.
t=(41m/s)/a
3.5m=(1/2)*a*((41m/s)/a)^2=(1/2)*a*(41m/s)^2/a^2=(1/2)*(41m/s)^2/a
a=(1/2)*(41m/s)^2/(3.5m)=(1/2)*41^2(m^2/s^2)/(3.5m) a=41^2(m/s^2)/( 2*3.5)=240m/s^2</span>
The equation for electric potential of a point charge is:
V=(k*q)/r where k=9*10^11 N m²/C², q is the charge and r is the distance from the charge to the point in which we are calculating the potential.
q=-5.2*10^-6 C
r=12 cm = 0.12 m
Now we plug in the numbers and get:
V=-3.9*10^5 Volts, so the correct answer is the second one.
