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shepuryov [24]
3 years ago
7

The thermosphere is characterized by a drastic increase in temperature. What is the reason for this increase? A. absorption of u

ltraviolet rays from the Sun B. decrease in moisture C. entrapment of greenhouse gases D. increase in air pressure
Physics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

A. absorption of ultraviolet rays from the Sun

Explanation:

The thermosphere helps protect and regulate Earth's temperature by absorbing much of the UV radiation and X-rays emitted by the Sun. When the Sun is most active, the thermosphere heats up and increases in size, increasing its protective power.

Just like in the oceans, the Earth's atmosphere experiences waves and tides that help move energy within it. The winds and the general circulation of the thermosphere are strong drivers of these tides and waves.

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What is work? how do we solve for work?​
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Answer: Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

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A stone is dropped from the top of a tower. What is its velocity after 3.0 seconds?
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For purposes of completing our calculations, we're going to assume that
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5 0
4 years ago
A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

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V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

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We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

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