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shepuryov [24]
4 years ago
7

The thermosphere is characterized by a drastic increase in temperature. What is the reason for this increase? A. absorption of u

ltraviolet rays from the Sun B. decrease in moisture C. entrapment of greenhouse gases D. increase in air pressure
Physics
1 answer:
ExtremeBDS [4]4 years ago
8 0

Answer:

A. absorption of ultraviolet rays from the Sun

Explanation:

The thermosphere helps protect and regulate Earth's temperature by absorbing much of the UV radiation and X-rays emitted by the Sun. When the Sun is most active, the thermosphere heats up and increases in size, increasing its protective power.

Just like in the oceans, the Earth's atmosphere experiences waves and tides that help move energy within it. The winds and the general circulation of the thermosphere are strong drivers of these tides and waves.

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If the Fox for an object on an incline is 350N,
Alinara [238K]
Pic? I need a pic thanks
5 0
3 years ago
¿Por qué es útil comprender tu condición física?
finlep [7]

Answer:

Es útil porque al saberlo evitas sobrexponerte a problemas como <em><u>enfermedades, desgarros o daños a largo plazo de tu cuerpo.</u></em>

Explanation:

When a person decides to start exercising or some type of physical activity, it is necessary for him to know how much his body can resist that activity during a defined period of time.

If in some way or another your body does not resist physical activity, you can hurt yourself, tear a ligament or muscle or get sick.

One of the most common diseases that almost nobody notices is the increase in circulatory and heart problems.

It is best to know your physical condition, how much weight you can carry with weights, or how long you can last doing physical activities.

4 0
3 years ago
A wire has a current density of 6.25 × 10 6 A / m 2 6.25×106 A/m2 . If the cross-sectional area of the wire is 1.79 mm 2 1.79 mm
joja [24]

Answer:17.44A

Explanation: Current density=I/Area

Area is given by 2.79mm^2=2.79×10^-6m^2

Current=I=current density ×Area=6.25×10^6 ×2.79×10^-6=17.44A

3 0
3 years ago
2. A can filled with sand has a mass of 0.65kg is swung overhead in a horizontal circle of radius 0.70m at a constant rate of 2.
Aliun [14]
<h3><u>Answer</u>;</h3>

≈ 5 Kgm²/sec

<h3><u>Explanation</u>;</h3>

Angular momentum is given by the formula

L = Iω, where I is the moment of inertia and ω is the angular speed.

I = mr², where m is the mass and r is the radius

 = 0.65 × 0.7²

 = 0.3185

Angular speed, ω = v/r

                              = (2 × 3.142 × r × 2.5) r

                              =  15.71

Therefore;

Angular momentum =  Iω

                                 = 0.3185 × 15.71

                                 = 5.003635

                                 <u>≈ 5 Kgm²/sec</u>

6 0
3 years ago
Driving 30.7 m/s in your car you see a dog up ahead and slam on your brakes. You stop just before hitting the dog after skidding
Nitella [24]

Answer: 2.74

Explanation:

We can solve this problem using the stopping distance formula:

d=\frac{(V_{o})^{2}}{2 \mu g}

Where:

d=132.1 m is the distance traveled by the car before it stops

V_{o}=30.7 m/s is the car's initial velocity

\mu is the coefficient of friction between the road and the tires

g=9.8 m/s^{2} is the acceleration due gravity

Isolating \mu:

\mu=\frac{2dg}{(V_{o})^{2}}

Solving:

\mu=\frac{2(132.1 m)(9.8 m/s^{2})}{(30.7 m/s)^{2}}

\mu=2.74 This is the coefficient of friction

7 0
3 years ago
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