A sample of aluminum metal has a mass of
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Answer:
Explanation:
There are two heat flows in this process and, since energy (heat) can neither be destroyed nor created, the energy change for the system must equal zero.
Data:
For Fe, m₁ = ?; C₁ = 0.452 J°C⁻¹g⁻¹; Ti = 2.00 °C; T_f = 21.50 °C
For H₂O, m₂ = 120 g; C₂ = 4.18 J°C⁻¹g⁻¹; Ti = 22.00 °C; T_f = 21.50 °C
Calculations:
1. Temperature changes
ΔT₁ = T_f - Ti = 21.50 °C - 2.00 °C = 19.50 °C
ΔT₂ = T_f - Ti = 21.50 °C - 22.00 °C = -0.50 °C
2. Mass of steel rod