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Lerok [7]
2 years ago
6

How many formula units of silver fluoride, AgF, are equal to 42.15 g of this substance?

Chemistry
1 answer:
4vir4ik [10]2 years ago
3 0

2.05 × 10²³ formula units

Given data:Mass of AgF =  43.15 gNumber of formula units = ?Solution:Number of moles of AgF:Number of moles = mass/ molar massNumber of moles = 43.15 g/ 126.87 g/molNumber of moles = 0.34 molNow Number of formula units will be determine by using Avogadro number.It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.The number 6.022 × 10²³ is called Avogadro number1 mole = 6.022 × 10²³ formula units0.34 mol × 6.022 × 10²³ formula units2.05 × 10²³ formula units

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Answer:

Weight of element X = 14.01 gram

Explanation:

Mass percentage is calculated by using :

Percent =\frac{Mass\ of\ element}{Total\ mass}\times 100

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Mass of O = 16.0 gram

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Mass of XO2 = mass of X + 2(mass of O)

Mass of XO2 = X + 2(16)

Mass of XO2 = X + 32

Total mass of O in the compound = 2(16) = 32 grams

Percent O = 69.55 %

Percent\ O =\frac{Mass\ of\ O}{Total\ mass\ of\ XO2}\times 100

69.55=\frac{32}{X+32}\times 100

\frac{69.55}{100}=\frac{32}{X+32}

0.6955=\frac{32}{X+32}

0.6955\times (X+32)=32

0.6955X+ 22.256=32

0.6955X=9.744

X=\frac{9.744}{0.6955}

X =14.01

weight of element X = 14.01 gram

14.01 is mass of nitrogen N

The correct formula of this element is NO2

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