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Lerok [7]
2 years ago
6

How many formula units of silver fluoride, AgF, are equal to 42.15 g of this substance?

Chemistry
1 answer:
4vir4ik [10]2 years ago
3 0

2.05 × 10²³ formula units

Given data:Mass of AgF =  43.15 gNumber of formula units = ?Solution:Number of moles of AgF:Number of moles = mass/ molar massNumber of moles = 43.15 g/ 126.87 g/molNumber of moles = 0.34 molNow Number of formula units will be determine by using Avogadro number.It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.The number 6.022 × 10²³ is called Avogadro number1 mole = 6.022 × 10²³ formula units0.34 mol × 6.022 × 10²³ formula units2.05 × 10²³ formula units

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What is the potential energy of the reactants from the following energy diagram?
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3 years ago
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Carbonates are typically insoluble, but one exception would be a carbonate containing what kind of cation? a) ammonium b) a tran
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For a carbonate containing a kind of cation, we have that Option 1 is the correct answer: ammonium.

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4 0
2 years ago
If the lab technician needs 30 liters of a 25% acid solution, how many liters of the 10% and the 30% acid solutions should she m
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Answer:

7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.

Explanation:

Let the volume of 10% acid solution used to make the mixture = x L

So, the volume of 30% acid solution used to make the mixture = y L

Total volume of the mixture = <u>x + y = 30 L .................. (1) </u>

For 10% acid solution:

C₁ = 10% , V₁ = x L

For 30% acid solution :

C₂ = 30% , V₂ = y L

For the resultant solution of sulfuric acid:

C₃ = 25% , V₃ = 30 L

Using  

C₁V₁ + C₂V₂ = C₃V₃

10×x + 30×y = 25×30

So,  

<u>x + 3y = 75 .................. (2) </u>

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6 0
3 years ago
8.43g of CaCl2·2H2O is dissolved in 40.0g of H2O. What is the molality of the solution? (Note that the H2O in the CaCl2·2H2O mus
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Answer:

[CaCl₂·2H₂O] = 1.43 m

Explanation:

Molality is mol of solute / kg of solvent.

Mass of solvent = 40 g

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Let's determine the moles of solute (mass / molar mass)

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Molality = 0.057 mol / 0.04 kg → 1.43

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3 years ago
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