Given
m1 = 15kg
vi1 = +20 m/s
vf1 = +5 m/s
m2 = 10 kg
vi2= -15 m/s
vf2 = ?
Procedure
Conservation of momentum, general law of physics according to which the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the total momentum of a system remains constant.
The speed of the 10kg Ball is 7.5m/s
Answer:
F = 2.6 x 10⁻²² N
Explanation:
According to the Coulomb's Law, the force of attraction or repulsion between two charges is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them. The formula for the force is given as follows:
F = k q₁ q₂/r²
where,
F = Force of Attraction or Repulsion = ?
q₁ = magnitude of first charge = charge on electron = 1.6 x 10⁻¹⁹ C
q₂ = magnitude of second charge = charge on proton = 1.6 x 10⁻¹⁹ C
k = Coulomb's Constant = 9 x 10⁰ N m²/C²
r = distance between the charges = 885 nm = 8.85 x 10⁻⁷ m
Therefore,
F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(8.85 x 10⁻⁷ m)²
<u>F = 2.6 x 10⁻²² N</u>
Answer:
amplitude is 8.92 cm
speed of block is 44.11 cm/s
Explanation:
given data
mass = 0.650 kg
spring constant = 18 N/m
speed = 47 cm/s = 0.44 m/s
speed at x point = 0.350 A
to find out
amplitude of subsequent oscillation
solution
we know here conservation of energy
maximum kinetic energy = maximum potential energy
here we know k is spring constant and m is mass and A is amplitude and v is velocity
so solve it we get
A =
put here all these value
A =
A = 0.08931 m
so amplitude is 8.92 cm
and
by conservation of energy
initial energy = final energy
=
solve we gey V
V =
put here value Vm = 0.47 , and x = 0.350
V =
V = 0.4411 m/s
so speed of block is 44.11 cm/s
Answer: mammals may be relatively better at solving problems than birds.
Answer:
The second trumpeter will be playing at frequency = 515 Hz
Explanation: Given that the note sounds lower and they can hear 20 beats in 4.0 s.
Beat frequency = 20/4 = 5 Hz
Beat frequency = F2 - F1
5 = 520 - F1
F1 = 520 - 5
F1 = 515 Hz
Since the note sound lower, the second trumpeter will be playing at 515 Hz frequency