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Lyrx [107]
3 years ago
15

A spring is compressed by 0.02m. Calculate the energy stored in the spring if the force constant is 400Nm-1

Physics
1 answer:
gogolik [260]3 years ago
4 0

Answer:

0.08 J

Explanation:

EE = ½ kx²

EE = ½ (400 N/m) (0.02 m)²

EE = 0.08 J

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What are the units for the spring constant, k? A. newton meters B. newton seconds C. newtons/meter D. newtons/second E. newtons/
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Answer:

C. N/m (newtons/meter)

Explanation:

Since the equation for potential energy for a spring is PE = 1/2kx², after you know <em>k </em>and <em>x</em>, you will get an answer in Joules.

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A 2.0 kg block is released from rest at the top of a curved incline in the shape of a quarter of a circle of radius R = 3.0 m. T
Zigmanuir [339]

The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy <em>PE</em> :

<em>PE</em> = <em>m g h</em>

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Energy is conserved throughout the block's descent, so that <em>PE</em> at the top of the curve is equal to kinetic energy <em>KE</em> at the bottom. Solve for the velocity <em>v</em> :

<em>PE</em> = <em>KE</em>

58.8 J = 1/2 <em>m v</em> ²

117.6 J = (2.0 kg) <em>v</em> ²

<em>v</em> = √((117.6 J) / (2.0 kg))

<em>v</em> ≈ 7.668 m/s ≈ 7.7 m/s

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3 years ago
44. A rescue helicopter is hovering over a person whose boat has sunk. One of the rescuers throws a life preserver straight down
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Answer:

18.4 m

Explanation:

(a)

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(b)

The vertical distance covered by the life preserver is given by

d=ut + \frac{1}{2}at^2

If we substitute all the values listed in part (a), we find

d=(1.40 m/s)(1.8 s)+\frac{1}{2}(9.8 m/s^2)(1.8 s)^2=18.4m

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What determines the pitch of a sound wave
saveliy_v [14]
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A sealed cubical container 10.0 cm on a side contains three times Avogadro's number of molecules at a temperature of 24.0°C. Fin
rodikova [14]

This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

PV = nRT

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

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T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

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P = 7407.78 KPa

Now, the force on one wall can be given as follows:

P =\frac{F}{A}\\\\F=PA

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

F=(7407.78\ KPa)(0.01\ m^2)\\

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<u></u>

Learn more about the general gas equation here:

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