Answer:
C₁ = 3 pF
C₂ = 6 pF
Explanation:
Let the capacitance be C₁ and C₂.
For parallel combination
C₁ +C₂ = 9
For series combination
C₁ X C₂ = 18
( 9-C₂ )X C₂ = 18
C₂²- 9C₂ +18 = 0
C₂ = 6 or 3.
C₁ = 3 or 6.
C₁ = 3 pF
C₂ = 6 pF
Answer:
(a) 21.36 ohms
(b) 5.62 A
Explanation:
Parameters given:
Potential difference, V = 120 V
Power, P = 674 W
(a) Power is given as:
P = V²/R
Where R is resistance
=> R = V²/P
R = 120²/674
R = 14400/674
R = 21.36 ohms
(b) Power is also given as:
P = I*V
Where I = Current (time rate of flow of Electric charge)
=> I = P/V
I = 674/120
I = 5.62 A
If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is
x-component = 88 · cosine(13°)
x-component = 88 · (0.9744)
<em>x-component = 85.74</em>
The first part is an acceleration that starts from rest. Distance is determined using the formula d=(1/2)at², where a is acceleration and t is time. Next is to determine the distance using the constant velocity. The formula that can be used is d=vt wherein v is velocity.
Answer:
F = 237 N
Explanation:
x(t) = 0.32sin(πt)
v(t) = 0.32πcos(πt)
a(t) = -0.32π²sin(πt)
a(1.5) = -0.32π²sin(π1.5) = 3.158... m/s²
F = ma = 75(3.158) = 236.870... N
