Answer:
crystalline and amorphous.
Explanation:
Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order
I can’t access the pictures. Sorry!
Answer:
The correct option is: (A) Ketones cannot be oxidized further
Explanation:
Oxidation refers to the gain of oxygen or the formation of carbon-oxygen bond (C-O bond).
Alcohols are organic compounds containing at least one hydroxyl group. These compounds can be further classified into <em>primary (R-CH₂-OH), secondary (R¹R²CH-OH) and tertiary alcohols (R¹R²R³C-OH).</em>
- The <u>partial oxidation of </u><u>primary alcohol</u><u> gives </u><u>aldehyde</u> (R-CHO). Further <u>oxidation of aldehyds gives </u><u>carboxylic acid </u>(R-COOH). <u>Primary alcohol can also be oxidized directly to carboxylic acid.</u> <em>However, the carboxylic acid can not be further oxidized.</em>
![R-CH_{2}-OH \overset{[O]}{\rightarrow} R-CHO \overset{[O]}{\rightarrow} R-COOH \\R-CH_{2}-OH \overset{[O]}{\rightarrow} R-COOH](https://tex.z-dn.net/?f=R-CH_%7B2%7D-OH%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R-CHO%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R-COOH%20%5C%5CR-CH_%7B2%7D-OH%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R-COOH)
- <u>Oxidation of </u><u>secondary alcohols</u><u> gives </u><u>ketones</u> (R¹R²C=O), <em>which can not be oxidized further.</em>
![R^{1}R^{2}CH-OH \overset{[O]}{\rightarrow} R^{1}R^{2}C=O](https://tex.z-dn.net/?f=R%5E%7B1%7DR%5E%7B2%7DCH-OH%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R%5E%7B1%7DR%5E%7B2%7DC%3DO)
- Whereas, tertiary alcohols are resistant to oxidation.
<u>Therefore, the correct statement regarding oxidation is </u><u>(A)</u><u> </u><em><u>Ketones cannot be oxidized further</u></em><u>.</u>
Answer :
(a) 
(b) 
(c) 
Explanation:
(a) cm/min to in/s
The conversion factor used :

and,

So, 

Thus, 
(b) 
The conversion factor used :

Thus, 
(c) 
The conversion factor used :

and,

So, 

Thus, 
C because we need materials in the lab